D = V1( t ) + 1/2g( t )^2
50m = 0m/s( t ) + 1/2(9.8m/s^2)*( t )^2
V1*t cancels out
50m = (4.9m/s^2)*(t)^2
50m/(4.9m/s^2) = t^2
Metres unit cancels out so we are left with s^2
10.204s^2 = t^2
Square root both sides to cancel out square
t = 3.19 s
Longitudinal waves travel through a series of compressions and rarefactions.
When a ball is thrown up by doing work, the velocity of the ball will be 2.6 m/s.
<h3>What is Work energy theorem?</h3>
It states that the Work done in moving a body is equal to the change in kinetic energy of the body
Kinetic energy = 1/2 mv²
Given is a ball of mass m = 0.750 kg and the work done on ball W = 2.50 J
The ball is initially at rest. So, initial velocity is zero. Then, change in kinetic energy will be
W= ΔK.E = K.Ef - K.Ei
According to work energy theorem, work done is
W = 2.5J = 1/2 x 0.750 x (v)² -0
v =2.6 m/s
Thus, the velocity of the ball is 2.6 m/s
Learn more about work energy theorem.
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