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4 years ago

On March 21, a stick casts the following shadow. What is the most likely time of day?

Physics

2 answers:

Tpy6a [65]4 years ago

8 0

Answer: Yep it is 9:00

Explanation:

jenyasd209 [6]4 years ago

5 0

Answer:

9:00 AM

Explanation:

I took the test and that was the answer

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At the race track, one race car starts its engine with a resulting intensity level of 104.0 dB at point P. Then 6 more cars star

dem82 [27]

To solve the problem it is necessary to apply the concepts related to sound intensity. The most common approach to sound intensity measurement is to use the decibel scale:

$\beta (dB) = 10log_{10}(\frac{I}{I_0})$

Where,

$I_0 = 1*10^{-12}$ is a reference intensity. It is the lowest or threshold intensity of sound a person with normal hearing can perceive at a frequency of 1000 Hz.

I = Sound intensity

Our values are given by,

$\beta = 104dB$

$\#Autos = 7$

For each auto the intensity would be,

$104 = 10log\frac{I}{1*10^{-12}}$

$10.4= log_{10} (\frac{I}{10^{-12}})$

$10^{10.4}*10^{-12}=I$

$I = 0.02511W/m^2$

Therefore the sound intesity for the 7 autos is

$I= 7* 0.02511$

$I = 0.1748W/m^2$

The sound level for the 7 cars in dB is

$\beta (dB) = 10log_{10}(\frac{0.1748}{1*10^{-12}})$

$\beta (dB) = 112.42dB$

8 0

3 years ago

Suppose you have a 75-watt light bulb that you leave turned on for two minutes. How much energy

victus00 [196]

Answer:

9000 J

Explanation:

Convert minutes to seconds.

2 min = 120 s

Power = energy / time

75 W = E / 120 s

E = 9000 J

5 0

2 years ago

A large grinding wheel in the shape of a solid cylinder of radius 0.330 m is free to rotate on a frictionless, vertical axle. A

ArbitrLikvidat [17]

Answer:

The mass of the solid cylinder is $m = 1612.5 \ kg$

Explanation:

From the question we are told that

The radius of the grinding wheel is $R = 0.330 \ m$

The tangential force is $F_t = 250 \ N$

The angular acceleration is $\alpha = 0.940 \ rad/s^2$

The torque experienced by the wheel is mathematically represented as

$\tau = I * \alpha$

Where I is the moment of inertia

The torque experienced by the wheel can also be mathematically represented as

$\tau = F_t * r$

substituting values

$\tau = 250 * 0.330$

$\tau = 82.5 \ N\cdot m$

$82.5 = I * \alpha$

$82.5 = I * 0.940$

$I = 87.8 \ kg \cdot m^2$

This moment of inertia can be mathematically evaluated as

$I = \frac{1}{2} * m* r^2$

substituting values

$87.8 = \frac{1}{2} * m* (0.330)^2$

=> $m = 1612.5 \ kg$

5 0

3 years ago

How does secondary succession help restore equilibrium to a region destroyed by a flood?

I am Lyosha [343]

Answer:

Explanation:

Ecological succession is a process of inhabiting a zoological area by a group of organisms. it involves many stages to reach the climax stage such as primary, secondary, tertiary names basing on the habitat where it occurs. once the organisms reach the most stable stage of the succession. thus it maintains equilibrium Succession helps restore the equilibrium of an ecosystem by forming up new species, diversifying species, and basically by replacing the damaged, deranged, or disturbed community. For instance, when a sudden climate change occurred in a community, such as drought, dryness, fire, or heat waves, all living things that depends on water or survives in a cool, wet environment will die or migrate somewhere else. Thus, leaving that community vacant and/or unoccupied by any living things. Succession, then, will take place in that area by going through various stages until reaching the climax stage, in which the ecosystem is complete again.

5 0

3 years ago

Consider a father pushing a child on a playground merry-go-round. The system has a moment of inertia of 84.4 kg · m². The father

natulia [17]

Answer:

Part a)

$KE = 101.4 J$