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e-lub [12.9K]
3 years ago
15

A police car moving at 36.0 m/s is chasing a speeding motorist traveling at 30.0 m/s. The police car has a siren that emits soun

d at 3550 Hz. What is the frequency that the motorist hears?
Physics
1 answer:
maxonik [38]3 years ago
5 0

Answer:

The frequency heard by the motorist is 4313.2 Hz.

Explanation:

let f1 be the frequency emited by the police car and f2 be the frequency heard by the motorist, let v1 be the speed of the police car and v2 be the speed of the motorist and v = 343 m/s be the speed of sound.

because the police car is moving towards the motorist at a higher speed, then the motorist will hear a increasing frequency and according to Dopper effect, that frequency is given by:

f1 =  [(v + v2/(v - v1))]×(f2)

   = [( 343 + 30)/(343 - 36)]×(3550)

   = 4313.2 Hz

Therefore, the frequency heard by the motorist is 4313.2 Hz.

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integrate both sides, the left side will be integrated from an initial voltage v to a final voltage V, and the right side from an initial time 0 to a final time t:

\int\limits^V_v {\frac{dV}{V} } =-\int\limits^t_0 {\frac{1}{RC} } \, dt

Evaluating the integrals:

ln(\frac{V}{v})=e^{\frac{-t}{RC} }

natural logarithm to both sides in order to isolate V:

V(t)=ve^{-\frac{t}{RC} }

Where the term RC is called time constant and is given by:

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Which two options would INCREASE the electric force between two charged particles?
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What type of charge will an object have if the object contains less protons than electrons?
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D=rt
when biker A catches biker B, the time they've been riding is the same, so 
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