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mote1985 [20]
3 years ago
14

The quantity demanded x for a product is inversely proportional to the cube of the price p for p > 1. When the price is $10 p

er unit, the quantity demanded is 64 units. The initial cost is $150 and the cost per unit is $2. What price will yield a maximum profit?

Mathematics
1 answer:
LenaWriter [7]3 years ago
7 0
Q(p) = k/p^3 . . . . . . . . we want to find k
q(10) = k/10^3 = 64
k = 64,000

Revenue = q(p)*p = 64000/p^2
Cost = 150 +2q = 150 +2*64000/p^3

Profit = Revenue -Cost = 64000/p^2(1 -2/p) -150

Differentiating to find the maximum profit, we have
.. dProfit/dp = -2(64000/p^3) +6(64000/p^4) = 0
.. -1 +3/p = 0
.. p = 3

A price of $3 per unit will yield a maximum profit.

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4 0
2 years ago
Help fast please I going to fail
Scilla [17]

Answer:

  1. 0.5
  2. 0.25
  3. 0.4
  4. 1.05
  5. 0.05
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4 0
2 years ago
How many solutions do these equations have y= 3x+4 y+6=3x
Nataly [62]

Answer:

Step-by-step explanation:

hello :

the system is :  y= 3x+4....(*)

                         y+6=3x....(**)

by (**) : y = 3x - 6

so : y= 3x+4

      y= 3x - 6

means :  3x+4 = 3x - 6

                     4= -6.......(false)

conclusion : no reals  solutions

5 0
3 years ago
Find the value of each variable in the parallelogram
melomori [17]

Alright.

For 7, you'll want to put congruent sides equal to each other, assuming they are parallelograms. So, you'll get the two equations:

3x+2=23

2y-7=9

Solve using GEMDAS/PEMDAS, and you'll get these answers.

3x+2=23

3x=21

x=7

2y-7=9

2y=2

y=1

For 8, you'll want to do the exact same thing, formatting the numbers to equal each other. You'll get these two equations:

3y+5=14

2x-5=17

Solving them would make:

3y+5=14

3y=9

y=3

2x-5=17

2x=22

x=11

For 9, you have to remember that the angle opposite of one angle in a defined parallelogram are congruent. Thus:

130=2h

5k=50

solve them and you get

h=65

k=10

___________________________________________

Hope that helped. Good luck.

5 0
3 years ago
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25.21 this is corect :D

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3 years ago
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