Solutions i found was m=4 or m=-2<span>
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The question is incomplete:
James has dimes and quarters saved up in his change jar. He has a total of 162 coins totaling $31.20 what is the total amount james has in quarters?
a. $10.00
b. $6.20
c.$15.50
d.$25.00
Answer:
d.$25.00
Step-by-step explanation:
With the information provided, you can write the following equations given that dimes are equal to 0.10 and quarters to 0.25 to determine the number of dimes and quarters that James has:
x+y=162 (1)
0.10x+0.25y=31.20 (2), where:
x is the number of dimes
y is the number of quarters
First, you can solve for x in (1):
x=162-y (3)
Then, you have to replace (3) in (2) and solve for y:
0.10(162-y)+0.25y=31.20
16.2-0.10y+0.25y=31.20
0.15y=31.20-16.2
0.15y=15
y=15/0.15
y=100
Finally, you have to replace the value of y in (3) to find x:
x=162-100
x=62
Now, you know that James has 100 quarters and you can multiply this number for the value of a quarter to find the amount James has in quarters:
100*0.25=25
According to this, the answer is that James has $25 in quarters.
Answer:
Step-by-step explanation:
Sounds as tho' possible answer choices were listed. Please, share them without being asked to do so. Thank you.
7√(x²) 7√(x²)
------------- = ----------------------
5 √(y³) 5√( y^(3/2) )
We want to get the fractional exponent out of the denominator. To do this, multiply both numerator and denominator by y^(1/2):
7√(x²) 7√(x²) y^(1/2) 7√(x²)·y^(1/2) 7x√y
------------- = --------------------- * ----------- = --------------------- = ----------
5 √(y³) 5√( y^(3/2) ) y^(1/2) 5 √(y²) 5y
This is the final answer. We have succeeded in removing radicals / fractional exponents from the denominator.
