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SashulF [63]
2 years ago
8

Fill in the blank to make the system have no solutions 2x+3y-5z=12 -4x-6y__ z=5

Mathematics
2 answers:
Lady_Fox [76]2 years ago
8 0

Answer:

10

Step-by-step explanation:

We see that: 2×2=4 and 3×2=6

therefore,5×2 = 10

AleksandrR [38]2 years ago
5 0

Answer:

19 dollars fortnite card

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WILL MARK BRAINLIEST!!!!!
statuscvo [17]

The shape with a rotational symmetry would remain the same when rotated

The shape with the smallest angle of rotational symmetry of 180 degrees is shape D

<h3>How to determine the shape?</h3>

To do this, we simply examine each of the options

<u>Shape A: Cross</u>

The shape has 4 equal sides.

So, the smallest angle of rotational symmetry is:

Angle = 360/4

Angle = 90

The smallest angle of rotational symmetry is 90 degrees

<u>Shape B: Star</u>

The shape has 5 vertices.

So, the smallest angle of rotational symmetry is:

Angle = 360/5

Angle = 72

The smallest angle of rotational symmetry is 72 degrees

<u>Shape C: Composite figure</u>

This shape has a square and a triangle merged together at two ends

This means that the smallest angle of rotational symmetry is a complete rotation of 360 degrees

<u>Shape D: Circle</u>

The circle is divided into two equal segments.

The angle on the straight line of each segment is:

Angle = 360/2

Angle = 180

The smallest angle of rotational symmetry is 180 degrees

Hence, the shape with the smallest angle of rotational symmetry of 180 degrees is shape D

Read more about rotational symmetry at:

brainly.com/question/12214455

8 0
2 years ago
If f(x)=x^1/2-x and g(x)=2x^3-x^1/2-x, find f(x)-g(x)
inn [45]
X^1/2 - x
-2x^3 - x^1/2 - x

-2x^3 - 2x
i think this is it
6 0
3 years ago
Read 2 more answers
Please help me asap have a great day
GREYUIT [131]

Answer:

C, 15

Step-by-step explanation:

i looked it up

5 0
3 years ago
What’s the answer to this question ?
PilotLPTM [1.2K]

Answer:

y=60h+2.5

Step-by-step explanation:

6 0
3 years ago
Which of these limits evaluate to 0?
Vikentia [17]
<h3>Answer: C) I and II only</h3>

===============================================

Work Shown:

Part I

\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{2-2}{2+2}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = \frac{0}{4}\\\\\\\displaystyle \lim_{x \to 2}\frac{x-2}{x+2} = 0\\\\\\

----------

Part II

\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{\sin(0)}{0+2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = \frac{0}{2}\\\\\\\displaystyle \lim_{x \to 0}\frac{\sin(x)}{x+2} = 0\\\\\\

----------

Part III

\displaystyle \lim_{x \to 5}\frac{x}{x} = \lim_{x \to 5}1\\\\\\\displaystyle \lim_{x \to 5}\frac{x}{x} = 1\\\\\\

7 0
2 years ago
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