Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Http://www.brooklyn.cuny.edu/bc/ahp/LAD/C3/C3_elecEnergy.html
^ this website might help with your question. = )
<h2>A is the correct answer!</h2><h3></h3><h3>Increase in food supply = more food = BIGGER POPULATION</h3><h3>Decrease in predators = more living rabbits = more reproduction</h3><h3></h3><h3>This scenario is VERY bad for the ecosystem and the rabbit population in the long term.</h3>
Carbon dioxide because people in other animals exhale carbon dioxide as a waste product. People and other animals need oxygen for plants produce oxygen during an important process called photosynthesis which turns the sun energy into nutrients so carbon dioxide would be the answer.
arteries, arterioles, capillary beds, venules, veins
