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cupoosta [38]
3 years ago
14

A student left a sealed jar of water outside her home. Water can be a solid, liquid, or gas. When she put it outside, the water

was a solid. Twelve hours later, the water had changed phase and was a liquid. What happened to the water molecules?
Chemistry
2 answers:
Vlad1618 [11]3 years ago
6 0

Answer:

When the state changes from solid to liquid it is called melting. This phenomenon occurs when energy is added causing the molecules in the solid state to move in an accelerated motion, dissociating from one another. Increase in energy increases the motion of each molecule. When the molecules have reached optimum levels of energy they begin to glide past each other, it is at this stage that the state is considered liquid.

Explanation:

GenaCL600 [577]3 years ago
3 0

The water molecules received enough energy through the heat for them to change to a liquid state by unfixing themselves from their fixed positions.

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Greeley [361]

Answer:

I think it's B

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5 0
3 years ago
Question 116 g of sunflower oil is
Luba_88 [7]
<h2>Answer:  125.41 mL</h2>

Explanation:

Volume = mass ÷ density

             =  116 g  ÷  0.925 g/mL

             =  125.41 mL

<h3>A 116 g of sunflower oil of 0.925 g/mL has a volume of 125.41 mL.</h3>
7 0
2 years ago
What two things must all matter have?
OleMash [197]

1.) Mass

2.) Can occupy space (Volume)

6 0
3 years ago
Read 2 more answers
How much heat is required to vaporize 25g of water at 100*c
ElenaW [278]

Answer:

Heat required = 13,325 calories or 55.75 KJ.

Explanation:

To convert a water to steam at 100 degree celsius to vapor, we have to give latent heat of vaporization to water

Which equals ,

Q = mL,

Where, m is the mass of water present

           L = specific latent heat of vaporization

Here , m= 25 gram

L equals to 533 calories (or 2230 Joules)

So, Q = 25×533 = 13,325 Calories

Or , Q = 55,750 Joules = 55.75 KJ

so, Heat required = 13,325 calories or 55.75 KJ.

4 0
3 years ago
A gas cylinder initially contains 463 L of gas at a pressure of 159 atm. If the final volume of gas is 817 L, what is the final
Agata [3.3K]

Answer:

The final pressure is 90.1 atm.

Explanation:

Assuming constant temperature, we can solve this problem by using <em>Boyle's Law</em>, which states:

  • P₁V₁=P₂V₂

Where in this case:

  • P₁ = 159 atm
  • V₁ = 463 L
  • P₂ = ?
  • V₂ = 817 L

We <u>input the given data</u>:

  • 159 atm * 463 L = P₂ * 817 L

And <u>solve for P₂</u>:

  • P₂ = 90.1 atm

The final pressure is 90.1 atm.

6 0
2 years ago
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