Empirical Formula = C20 H60 HG1 S1 O4 (numbers should be in subscript)
Percent Composition =
MG = 43%
S = 56.8%
Answer:
3.8 g/mL
Explanation:
From the question given above, the following data were obtained:
Volume of Water = 60 mL
Volume of Water + Object = 73.5 mL
Mass of object = 51.3 g
Density of object =?
Next, we shall determine the volume of the object. This can be obtained as follow:
Volume of Water = 60 mL
Volume of Water + Object = 73.5 mL
Volume of object =?
Volume of object = (Volume of Water + Object) – (Volume of Water)
Volume of object = 73.5 – 60
Volume of object = 13.5 mL
Finally, we shall determine the density of the object as illustrated below:
Volume of object = 13.5 mL
Mass of object = 51.3 g
Density of object =?
Density = mass /volume
Density of object = 51.3 /13.5
Density of object = 3.8 g/mL
Thus, the density of the object is 3.8 g/mL
PE= weight x height. (remember weight is the force of gravity acting on objects...NOT the same as mass)
PE=3*2*9.8
PE=6*9.8
PE=58.8 J (for joules which is the unit for both Kinetic and potential energy)
Hope this helps :D
Answer:
6.grass
7.xylem
8.oval
9. poor growth of bones and teetn
The chemical property of mercury is that it reacts with oxygen