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aleksandr82 [10.1K]
2 years ago
9

The photo shows an old-fashloned mercury thermometer. Mercury is a liquid metal that expands when It Is heated. Mercury Narrow t

ube Bulb with thin glass covering Which statement best describes how the thermometer's bulb works?
A. The thin glass covering transfers thermal energy to the mercury so it can start to expand sooner.
B. The mercury easily transfers thermal energy so the thin glass covering can start to expand, C. The thin glass covering reflects thermal energy to stop the mercury from expanding, D. The mercury reflects thermal energy so the speed of energy transfer through the glass happens quickly.​
Chemistry
2 answers:
natta225 [31]2 years ago
8 0

Answer:

A

Explanation:

I took the test a p e x approved

Hope this helps plz hit the crown :D

Tom [10]2 years ago
4 0

Answer:

A

Explanation:

The thin glass covering transfers thermal energy just like putting normal glass in hot substance transfers heat to the mercury, mercury is a metal that is liquid at room temperature and freezes at about 40° celsius which is why it is used for measuring temperature of mostly humans

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Determine the empirical formula of the following compound if a sample contains 5.28 gsn and 3.37 gf.
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Answer:

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Explanation:

you  divide by the smallest number which is 3.37

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Which of the following have deliquescent Nature ? ​
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How many moles of hydrogen gas will form 1.35 L of a 2.75 M Hcl solution reacts?
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Water (with density of 1000 kg/m3) with the mass flowrate of 10 kg/sec is flowing into an empty tank. The outlet volumetric flow
Montano1993 [528]

Explanation:

Apply the mass of balance as follows.

   Rate of accumulation of water within the tank = rate of mass of water entering the tank - rate of mass of water releasing from the tank

         \frac{d}{dt}(\rho V) = 10 - \rho \times (0.01 h)

      \rho A_{c} \frac{dh}{dt} = 10 - (0.01) \rho h

   \frac{dh}{dt} + \frac{0.01 \rho h}{\rho A_{c}} = \frac{10}{\rho A_{c}}

          [/tex]\frac{dh}{dt} + \frac{0.01}{0.01}h[/tex] = \frac{10}{\rho A_{c}}

                       A_{c} = 0.01 m^{2}

              \frac{dh}{dt} + h = 1

                  \frac{dh}{dt} = 1 - h

               \frac{dh}{1 - h} = dt  

                \frac{ln(1 - h)}{-1} = t + C      

Given at t = 0 and V = 0  

                         A \times h = 0  

 or,                     h = 0

                 -ln(1 - h) = t + C

Initial condition is -ln(1) = 0 + C

                                C = 0  

                So,   -ln(1 - h) = t

or,                      t = ln (\frac{1}{1 - h})  ........... (1)

(a)    Using equation (1) calculate time to fill the tank up to 0.6 meter from the bottom as follows.

                    t = ln (\frac{1}{1 - h})  

                     t = ln (\frac{1}{1 - 0.6})  

                        = ln (\frac{1}{0.4})

                        = 0.916 seconds

(b)   As maximum height of water level in the tank is achieved at steady state that is, t = \infty.  

                    1 - h = exp (-t)

                    1 - h = 0  

                         h = 1

Hence, we can conclude that the tank cannot be filled up to 2 meters as maximum height achieved is 1 meter.

                 

8 0
3 years ago
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