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Ierofanga [76]
3 years ago
10

Use the numbers 8,6, and 2 and one operation to write an expression that includes an exponent and has a value of 8. Use each num

ber only once
Mathematics
1 answer:
omeli [17]3 years ago
8 0

6 + 2^1 = 8 is the expression that includes an exponent and has a value of 8

<em><u>Solution:</u></em>

Given that, we have to use numbers 8, 6, and 2 and one operation to write an expression that includes an exponent and has a value of 8

We are asked to use each number only once

<em><u>Given conditions:</u></em>

We have to use an operation and an exponent

The exponent corresponds to the number of times the base is used as a factor.

We have to get 8 as result

Since 6 is higher number, we can use exponent for 2

We can raise 2 to power of 1

<em><u>The required expression:</u></em>

6 + 2^1 = 8

Here we have the satisfied the given condition of using exponent and an operation ( addition is used ) and numbers are used only once

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-3(x + 2) + (x – 3)x=

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E) none of the above
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dolphi86 [110]

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4 0
3 years ago
Pierre wants to make tables and chairs. He has a total of 220220 wooden boards and 760760 nails. 13 T+8 C \leq 22013T+8C≤220 rep
Virty [35]

Solution:

Number of wooden boards that Pierre possess= 220

Number of nails that Pierre have= 760

The two expression which represents the number of tables T and chairs C he can make with 220 wooden boards and 760 nails

1. 13 T+8 C≤220

2. 48 T+37 C≤760

We can solve it by two methods, either graphically or by finding their point of intersections,as these two are inequalities in two variable

Equation (1) × 37 - Equation (2) × 8

481 T + 296 C-384 T -296 C≤8140 - 6080

97 T ≤ 2060

T ≤ 21.23(approx)

Putting the value of T in equation (1),

13 × 21.23 + 8 C ≤ 220

347.80 + 8 C≤220

8 C ≤ 220 - 347.80

8 C≤-127.80

As, the value of Chairs (C) can't be negative.

So, the two inequalities which represents number of chairs and number of tables is incorrect.

So, we can't find total number of chairs and total number of tables with the given inequalities.

5 0
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