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Juliette [100K]
3 years ago
15

Percent decrease in the value of the car

Mathematics
2 answers:
Neko [114]3 years ago
8 0

Answer:

45% value looked it up

Step-by-step explanation:

byéeeee

fenix001 [56]3 years ago
7 0

Answer:

Donde esta el foto

Step-by-step explanation:

translation: how do we answer the mf question without context

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aev [14]
The answer to your question is 11 world championships
8 0
3 years ago
Find the gcf for the list. 28y4, 20y3
blagie [28]
GCF of 28y^4 and 20y^3 is 4y^3
3 0
3 years ago
please help will give brainlest+30 points Snowy's Snow Cones has a special bubble gum snow cone on sale. The cone is a regular s
natali 33 [55]

Answer:

Hello There!

`~~~~~~~~~~~~~~~~~~~~~

If you subtract the volume of the sphere from the cone, you'll get the volume you can fill with flavored ice. Right?

Volume (sphere) = \frac{4}{3}\pi r^3

Volume(sphere) = \frac{1}{3}\pi r^2 . h

So that means, The volume left to put in flavored ice is :

Volume(sphere) = \frac{1}{3}\pi r^2h - \frac{4}{3}\pi r^2

So putting in the value for radius and height of the cone and radius of the sphere in the 2nd term will do the thing, I think.

.......

Okay, I think they didn't raise the power but wrote the exponent beside the number. It must be c. They wrote 32 so as to say 3^2 and wrote 0.553 to say (0.55)^3

So the answer is (C)

Hope this helped you. Brainliest would be nice!

5 0
3 years ago
Read 2 more answers
How do i solve for x? *you have to show work*
eduard
1) Factor the equation first:

2e^{2x} + 4xe^{2x} = 0
e^{2x}(2 + 4x) = 0

So either e^{2x} = 0 or 2 + 4x = 0. But e^{2x} = 0 can never equal 0! So, we only need to solve for the second equation:

2 + 4x = 0
\bf x = {-\frac{1}{2}}

2) First, single out the term with the exponent:

2 + 3(4^{2x - 1}) = 43
3(4^{2x - 1}) = 41
4^{2x - 1} = \frac{41}{3}

Now, taking the log base 4 of each side gives us

2x - 1 = \log_4 \frac{41}{3}

and we can now solve for x:

2x - 1 = \log_4 \frac{41}{3}
2x = 1 + \log_4 \frac{41}{3}
2x = \log_4 4 + \log_4 \frac{41}{3}
2x = \log_4 \frac{164}{3}
x = \frac{1}{2} \log_4 \frac{164}{3}
x = \log_4 \sqrt \frac{164}{3}
\bf x = \log_4 2 \sqrt \frac{41}{3}
8 0
3 years ago
Pls help me with an accurate answer I can’t seem to solve it. Tyy :)
castortr0y [4]

Answer:

.<em><u>O</u></em><em><u>P</u></em><em><u>T</u></em><em><u>I</u></em><em><u>O</u></em><em><u>N</u></em><em><u> </u></em><em><u>A</u></em><em><u>:</u></em><em><u>2</u></em><em><u>0</u></em><em><u>°</u></em>

SINCE THE BOTH SIDE OF LINE IS PERPENDICULAR

THEREFORE,90°

THEREFORE,

4X-10+X=90.

5X-10=90

5X=100

X=20°

7 0
3 years ago
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