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Ilia_Sergeevich [38]
2 years ago
15

What does the ideal gas law allow a scientist to calculate that the other laws do not?

Physics
2 answers:
Daniel [21]2 years ago
6 0
The ideal gas law.
PV=nRT
P=presure
V=volume
n=number of moles
R=Gas costant
T=temperature.

Answer: a. Number of moles.
Vladimir [108]2 years ago
4 0

Answer:

A). number of moles

Explanation:

I took the test. It is correct.

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Which, if any, of the heat engines violate(s) the second law of thermodynamics?
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The second law states that the total entropy can never decrese over time for an isolated system
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What are groups 1,2 and 3 examples of on the periodic table
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<span>The number of the group identifies the column of the standard periodic table in which the element appears.</span>
Group 1 contains the  alkali metals ( lithium<span> (</span>Li<span>), </span>sodium<span> (</span>Na<span>), </span>potassium<span> (</span>K<span>), </span>rubidium<span> (</span>Rb<span>), </span>caesium<span> (</span>Cs<span>), and </span>francium(Fr).)<span>
Group 2 contains the alkaline earth metals (</span> beryllium<span> (</span>Be),magnesium<span> (</span>Mg<span>), </span>calcium<span> (</span>Ca<span>), </span>strontium<span> (</span>Sr<span>), </span>barium<span> (</span>Ba<span>) and </span>radium<span> (</span>Ra<span>) )
Group 3: </span><span> Scandium (Sc) and yttrium (Y) </span>
4 0
2 years ago
Even, in 1921, the Dodge Brothers built a boat named the SS Delphine and it had a whopping 3000 HP. So, how much horsepower woul
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Answer: I am getting a result around the 54,800 area, so I am selecting the 55,000 HP answer.

7 0
2 years ago
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What prevents the pressure from increasing as a cloud contracts due to its gravity?
Vesnalui [34]

Thermal energy is converted to radiative energy via molecular collisions and released as photons.

4 0
2 years ago
If the second harmonic of a certain string is 42 Hz, what is the fundamental frequency of the string?
sdas [7]
Data:
f_{2} = 42 Hz
n (Wave node)
V (Wave belly) 
L (Wave length)
<span>The number of bells is equal to the number of the harmonic emitted by the string.
</span>
f_{n} =  \frac{nV}{2L}

Wire 2 → 2º Harmonic → n = 2

f_{n} = \frac{nV}{2L}
f_{2} = \frac{2V}{2L} &#10;
2V =  f_{2} *2L
V =  \frac{ f_{2}*2L }{2}
V =  \frac{42*2L}{2}
V =  \frac{84L}{2}
V = 42L

Wire 1 → 1º Harmonic or Fundamental rope → n = 1


f_{n} = \frac{nV}{2L}
f_{1} = \frac{1V}{2L}
f_{1} =  \frac{V}{2L}

If, We have:
V = 42L
Soon:
f_{1} = \frac{V}{2L}
f_{1} = \frac{42L}{2L}
\boxed{f_{1} = 21 Hz}

Answer:

<span>The fundamental frequency of the string:
</span>21 Hz

7 0
3 years ago
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