Lighter molecules move fast and escape from the upper atmosphere relatively quickly.
To find the answer, we have to know more about the lighter isotopes.
<h3>
What are lighter isotopes?</h3>
- Lighter molecules are mobile and soon leave the higher atmosphere.
- A particular element's stable isotopes have slightly different atomic masses and quantum mechanical energies.
- The lighter isotope of an element's chemical bonds are more easily broken than the heavier isotope's.
- As a result, the light isotope typically benefits from chemical reactions.
Thus, we can conclude that, lighter molecules move fast and escape from the upper atmosphere relatively quickly.
Learn more about the isotopes here:
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Answer:
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Explanation:
Answer:
a body which was thrown in space ,moves under the influence of gravity only is defined as projectile.
Answer:
The resultant force would (still) be zero.
Explanation:
Before the 600-N force is removed, the crate is not moving (relative to the surface.) Its velocity would be zero. Since its velocity isn't changing, its acceleration would also be zero.
In effect, the 600-N force to the left and 200-N force to the right combines and acts like a 400-N force to the left.
By Newton's Second Law, the resultant force on the crate would be zero. As a result, friction (the only other horizontal force on the crate) should balance that 400-N force. In this case, the friction should act in the opposite direction with a size of 400 N.
When the 600-N force is removed, there would only be two horizontal forces on the crate: the 200-N force to the right, and friction. The maximum friction possible must be at least 200 N such that the resultant force would still be zero. In this case, the static friction coefficient isn't known. As a result, it won't be possible to find the exact value of the maximum friction on the crate.
However, recall that before the 600-N force is removed, the friction on the crate is 400 N. The normal force on the crate (which is in the vertical direction) did not change. As a result, one can hence be assured that the maximum friction would be at least 400 N. That's sufficient for balancing the 200-N force to the right. Hence, the resultant force on the crate would still be zero, and the crate won't move.
