Answer:
The discharge rate is 
Explanation:
From the question we are told that
The diameter is 
The head is 
The coefficient of contraction is 
The coefficient of velocity is 
The radius is mathematically evaluated as

substituting values


The area is mathematically represented as

substituting values


The discharge rate is mathematically represented as

substituting values


Because the four outer planets are comprised of mostly gases give me a thanks or brainiest answer if this helps!
Answer:
(a) t = 1.14 s
(b) h = 0.82 m
(c) vf = 7.17 m/s
Explanation:
(b)
Considering the upward motion, we apply the third equation of motion:

where,
g = - 9.8 m/s² (-ve sign for upward motion)
h = max height reached = ?
vf = final speed = 0 m/s
vi = initial speed = 4 m/s
Therefore,

<u>h = 0.82 m</u>
Now, for the time in air during upward motion we use first equation of motion:

(c)
Now we will consider the downward motion and use the third equation of motion:

where,
h = total height = 0.82 m + 1.8 m = 2.62 m
vi = initial speed = 0 m/s
g = 9.8 m/s²
vf = final speed = ?
Therefore,

<u>vf = 7.17 m/s</u>
Now, for the time in air during downward motion we use the first equation of motion:

(a)
Total Time of Flight = t = t₁ + t₂
t = 0.41 s + 0.73 s
<u>t = 1.14 s</u>
4 atoms
Explanation:
On the product side, we expect to find 4 atoms of the product.
An atom is the smallest indivisible particle that takes part in a chemical reaction.
An element is a distinct substance that cannot be split-up into simpler substances. Such substances consist of only one kind of atom.
In this reaction we have:
2 elements: Mg O
on the reactant side:
We have two moles of Mg: 2 atoms of Mg
1 mole of oxygen gas: 2 atoms of O
total atoms: 4 atoms
According to the law of conservation of matter "in a chemical reaction, matter is neither created nor destroyed".
We expect to find 4 atoms of products which is MgO on the product side.
2Mg + O₂ → 2MgO + heat
Learn more:
Conservation of matter brainly.com/question/2190120
#learnwithBrainly
Answer:
Plug in the given values and solve for the final velocity. Remember, when the ball is on the ground it has a height of zero.
Explanation: