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ELEN [110]
2 years ago
15

Given the 1-m stick shown below, which is held by a thread at its center. Block 1 is 15 N held at the 10 cm mark, while block 2

is of unknown weight. If the meterstick is balanced when block 2 is at the 80 cm mark. What is the mass of block 2?
Physics
1 answer:
sattari [20]2 years ago
7 0
Jejebsjwiebrirndjdjdjjrkdid
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A sharp edged orifice with a 60 mm diameter opening in the vertical side of a large tank discharges under a head of 6 m. If the
Ierofanga [76]

Answer:

The discharge rate is Q = 0.0192 \  m^3 /s

Explanation:

From the question we are told that

   The  diameter is  d =  60 \ mm   =  0.06 \ m

    The  head is  h  =  6 \ m

     The  coefficient of contraction is  Cc  =  0.68

     The  coefficient of  velocity is  Cv  =  0.92

The radius is mathematically evaluated as

         r =  \frac{d}{2}

substituting values

        r =  \frac{ 0.06 }{2}

        r =  0.03 \ m

The  area is mathematically represented as

      A =  \pi r^2

substituting values

      A =  3.142 *  (0.03)^2

      A = 0.00283 \ m^2

 The  discharge rate is mathematically represented as

        Q =  Cv *Cc  *  A  *  \sqrt{ 2 * g *  h}

substituting values

       Q = 0.68 *  0.92*   0.00283  *  \sqrt{ 2 * 9.8 *  6}

       Q = 0.0192 \  m^3 /s

6 0
2 years ago
Why do the four outer planets have lower density than the four inner planets?
Marrrta [24]
Because the four outer planets are comprised of mostly gases give me a thanks or brainiest answer if this helps! 
4 0
3 years ago
A swimmer bounces straight up from a diving board and falls feet first into a pool. She starts with a velocity of 4.00 m/s, and
garri49 [273]

Answer:

(a) t = 1.14 s

(b) h = 0.82 m

(c) vf = 7.17 m/s

Explanation:

(b)

Considering the upward motion, we apply the third equation of motion:

2gh = v_f^2 - v_i^2

where,

g = - 9.8 m/s² (-ve sign for upward motion)

h = max height reached = ?

vf = final speed = 0 m/s

vi = initial speed = 4 m/s

Therefore,

(2)(9.8\ m/s^2)h = (0\ m/s)^2-(4\ m/s)^2\\

<u>h = 0.82 m</u>

Now, for the time in air during upward motion we use first equation of motion:

v_f = v_i + gt_1\\0\ m/s = 4\ m/s + (-9.8\ m/s^2)t_1\\t_1 = 0.41\ s

(c)

Now we will consider the downward motion and use the third equation of motion:

2gh = v_f^2-v_i^2

where,

h = total height = 0.82 m + 1.8 m = 2.62 m

vi = initial speed = 0 m/s

g = 9.8 m/s²

vf = final speed = ?

Therefore,

2(9.8\ m/s^2)(2.62\ m) = v_f^2 - (0\ m/s)^2\\

<u>vf = 7.17 m/s</u>

Now, for the time in air during downward motion we use the first equation of motion:

v_f = v_i + gt_1\\7.17\ m/s = 0\ m/s + (9.8\ m/s^2)t_2\\t_2 = 0.73\ s

(a)

Total Time of Flight = t = t₁ + t₂

t = 0.41 s + 0.73 s

<u>t = 1.14 s</u>

7 0
2 years ago
Magnesium is a highly flammable element which is easily combustible in the presence of oxygen:
NemiM [27]

4 atoms

Explanation:

On the product side, we expect to find 4 atoms of the product.

    An atom is the smallest indivisible particle that takes part in a chemical reaction.

    An element is a distinct substance that cannot be split-up into simpler substances. Such substances consist of only one kind of atom.

    In this reaction we have:

       2 elements:             Mg                O

on the reactant side:

   We have two moles of Mg:   2 atoms of Mg

            1 mole of oxygen gas:   2 atoms of O

                             total atoms:    4 atoms

According to the law of conservation of matter "in a chemical reaction, matter is neither created nor destroyed".

We expect to find 4 atoms of products which is MgO on the product side.

              2Mg + O₂ →  2MgO + heat

Learn more:

Conservation of matter brainly.com/question/2190120

#learnwithBrainly

     

   

       

3 0
3 years ago
Read 2 more answers
A 1.5 kg ball is dropped from a height of 2.Gm. Assuming energy is
Vikki [24]

Answer:

Plug in the given values and solve for the final velocity. Remember, when the ball is on the ground it has a height of zero.

Explanation:

6 0
2 years ago
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