<span>public void myMethod(int w, int y, int z) {
</span>int a, b, c, d, e, f, g, h, i, j, k, l;
<span>a = w * z;
</span>b = w * z + y;
c = w * -z;
d = w * --z + y++;
e = w * z-- + ++y<span> ;
</span>f = w + z * y;
g = w – y + z;
h = (w + y) * z;
i = y / w;
j = y / z;
k = w % y;
<span>l = y % w;
</span>System.out.println( "%d %d %d %d %d %d %d %d %d %d %d %d", a,b,c,d,e,f,g,h,i,j,k);
}
To use
myMethod(2, 7, 12);
Answer:
Explanation:
#include <stdio.h>
int main(void)
{
int num, rem;
printf("Enter a number: ");
scanf("%d", &num);
printf("Roman numerals: ");
while(num != 0)
{
if (num >= 1000) // 1000 - m
{
printf("m");
num -= 1000;
}
else if (num >= 900) // 900 - cm
{
printf("cm");
num -= 900;
}
else if (num >= 500) // 500 - d
{
printf("d");
num -= 500;
}
else if (num >= 400) // 400 - cd
{
printf("cd");
num -= 400;
}
else if (num >= 100) // 100 - c
{
printf("c");
num -= 100;
}
else if (num >= 90) // 90 - xc
{
printf("xc");
num -= 90;
}
else if (num >= 50) // 50 - l
{
printf("l");
num -= 50;
}
else if (num >= 40) // 40 - xl
{
printf("xl");
num -= 40;
}
else if (num >= 10) // 10 - x
{
printf("x");
num -= 10;
}
else if (num >= 9) // 9 - ix
{
printf("ix");
num -= 9;
}
else if (num >= 5) // 5 - v
{
printf("v");
num -= 5;
}
else if (num >= 4) // 4 - iv
{
printf("iv");
num -= 4;
}
else if (num >= 1) // 1 - i
{
printf("i");
num -= 1;
}
}
return 0;
}
The Microsoft project software is designed in assisting the project manager in formulating plans, distributing resources to certain tasks, progress monitoring, budget management and analysis of workloads.
I hope I was able to help you. Thank you for posting your question here at Brainly.
its answer in binary is 1000 and in decimal is 8.
I have concluded the answer is a
