Para saan po yung points dito?

What is an example of a hard skill?

Serjik [45]

3 would be self management

4 0

3 years ago

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Bytes are typically represented with a lowercase b and bits with an uppercase B. true or false

34kurt

Answer:

False

Explanation:

Byte(B) is uppercase

bit(b) is lowercase

Good way to remember is that its takes 8 bits makes a byte. In other word, a byte is bigger than a bit so it makes sense that byte is uppercase.

7 0

3 years ago

Answer the following questions for Web browser and Web server software: 1. What functions should this software application provi

timurjin [86]

Answer:

Explanation:

Functions should a software application provide to keep a web browser secured

1) The web browser should always be updated, so kindly keep the "automatic update" option enable on your browser settings so that whenever the browser gets an update, it will be updated automatically.

2) Always keep the third party cookies disabled because there are so many unauthorized and phishing sites over the internet they may lead the browser unsafe and cause very higher security risk so block all the third party sites and cookies from the browser

Functions should a software application prohibit to keep a web browser secured

1) Do not store passwords on your web browser, deny the "store password" option on your browser settings. Even if you store passwords on your web browser do set a very strong master password to access all the stored passwords.

2) Do not click on unwanted, unknown hyperlinks. There will be many unsolicited attachments, PDFs, DOCs, files, etc over the internet so do not open or download it unnecessarily.

Functions should a software application provide to keep a web server secured

1) Always use an application scanner. Whenever you install or download any new applications do scan the application before accessing it.

2) Install all the security patches because there are more number of hackers over the internet so do not deny installing the security patcheds on time.

Functions should a software application prohibit to keep a web server secured

1) When an application is not in use for long time, better uninstall it because they are actually of no use so do uninstall all the unwanted softwares or applications along with extensions.

2) There may be scripts, files, setups, codes stored on the web server unknowingly so do check it and delete all the sample scripts, files and codes from the web server.

5 0

3 years ago

Plz can someone tell me the answers ?

Ganezh [65]

Answer:

you can

Explanation:

you can

5 0

3 years ago

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a cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits such that the giv

Leokris [45]

Using the knowledge in computational language in C++ it is possible to write a code that cryptarithm is a mathematical puzzle where the goal is to find the correspondence between letters and digits

<h3>Writting the code:</h3>

#include <bits/stdc++.h>

using namespace std;

// chracter to digit mapping, and the inverse

// (if you want better performance: use array instead of unordered_map)

unordered_map<char, int> c2i;

unordered_map<int, char> i2c;

int ans = 0;

// limit: length of result

int limit = 0;

// digit: index of digit in a word, widx: index of a word in word list, sum: summation of all word[digit]

bool helper(vector<string>& words, string& result, int digit, int widx, int sum) {

if (digit == limit) {

ans += (sum == 0);

return sum == 0;

}

// if summation at digit position complete, validate it with result[digit].

if (widx == words.size()) {

if (c2i.count(result[digit]) == 0 && i2c.count(sum%10) == 0) {

if (sum%10 == 0 && digit+1 == limit) // Avoid leading zero in result

return false;

c2i[result[digit]] = sum % 10;

i2c[sum%10] = result[digit];

bool tmp = helper(words, result, digit+1, 0, sum/10);

c2i.erase(result[digit]);

i2c.erase(sum%10);

ans += tmp;

return tmp;

} else if (c2i.count(result[digit]) && c2i[result[digit]] == sum % 10){

if (digit + 1 == limit && 0 == c2i[result[digit]]) {

return false;

}

return helper(words, result, digit+1, 0, sum/10);

} else {

return false;

}

// if word[widx] length less than digit, ignore and go to next word

if (digit >= words[widx].length()) {

return helper(words, result, digit, widx+1, sum);

}

// if word[widx][digit] already mapped to a value

if (c2i.count(words[widx][digit])) {

if (digit+1 == words[widx].length() && words[widx].length() > 1 && c2i[words[widx][digit]] == 0)

return false;

return helper(words, result, digit, widx+1, sum+c2i[words[widx][digit]]);

}

// if word[widx][digit] not mapped to a value yet

for (int i = 0; i < 10; i++) {

if (digit+1 == words[widx].length() && i == 0 && words[widx].length() > 1) continue;

if (i2c.count(i)) continue;

c2i[words[widx][digit]] = i;

i2c[i] = words[widx][digit];

bool tmp = helper(words, result, digit, widx+1, sum+i);

c2i.erase(words[widx][digit]);

i2c.erase(i);

}

return false;

}

void isSolvable(vector<string>& words, string result) {

limit = result.length();

for (auto &w: words)

if (w.length() > limit)

return;

for (auto&w:words)

reverse(w.begin(), w.end());

reverse(result.begin(), result.end());

int aa = helper(words, result, 0, 0, 0);

}

int main()

{

ans = 0;

vector<string> words={"GREEN" , "BLUE"} ;

string result = "BLACK";

isSolvable(words, result);

cout << ans << "\n";

return 0;

}

See more about C++ code at brainly.com/question/19705654

#SPJ1

3 0

2 years ago