D because the y-intercept is at -5 like shown in the equation, and the slope equals to 1, and I do believe that the bold line means that it is less than or equal to, just like the equation says.
Answer:
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
Step-by-step explanation:
We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 16 - 1 = 15
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of
). So we have T = 2.9467
The margin of error is:
M = T*s = 2.9467*0.058 = 0.171
In which s is the standard deviation of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg
The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.
The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.
Answer:
x = -1.5625
Step-by-step explanation:
Solve for x:
-8 x - 12.5 = 0
Add 12.5` to both sides:
(12.5 - 12.5) - 8 x = 12.5
12.5 - 12.5 = 0:
-8 x = 12.5
Divide both sides of -8 x = 12.5 by -8:
(-8 x)/(-8) = 12.5/(-8)
(-8)/(-8) = 1:
x = 12.5/(-8)
12.5/(-8) = -1.5625:
Answer: x = -1.5625
2 2/3 ÷ 5/6 = 3.2 is the answer
use this formula Sn=n/2[2a+(n-1)d]
here,d=a2-a1 and n= no. Of terms
Step-by-step explanation:
S8=8/2[2(1)+(8-1)2]
S8=64