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brilliants [131]
3 years ago
15

Ruby conducted a survey and found that 5/6 of her classmates have a pet and 2/3 of them are dogs what fraction of her classmates

has dogs
Mathematics
1 answer:
lina2011 [118]3 years ago
7 0
This is how I would solve it, I would act as if there were 36 people in the class.
36÷6=6×5=30
30÷3=10×2=20
20/36=10/18=5/9
You could also try another number such as 24;
24×(5÷6)=20
20×(2/3)=13.3(3 repeating)
13.333/24=5/9
5/9 people have dogs.
Tell me if this helps.
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Simplify the expression. <br><br>tan(-x)csc(-x)/sec(-x)cot (-x)
Scrat [10]
Tan(-x)csc(-x)sec -1  (-x)cot(-x) i am not sure, I hope you get a good grade, this is what i got.. ',: (
5 0
2 years ago
Solve the system of equations given . -2x+5y=-3
algol13

For this case we have the following system of equations:

-2x + 5y = -3\\y-15 = 3x

We multiply the second equation by -5:

-5y + 75 = -15x

Now we add the equations:

-2x-5y + 5y + 75 = -3-15x\\-2x + 75 = -3-15x\\-2x + 15x = -75-3\\13x = -78\\x = \frac {-78} {13}\\x = -6

We find the value of the variable "y":

y = 3x + 15\\y = 3 (-6) +15\\y = -18 + 15\\y = -3

THE solution is: (-6, -3)

Answer:

(-6, -3)

3 0
3 years ago
Jim, Carla and Tomy are members of the same family. Carla is 5 years older than Jim. Tomy is 6 years older than Carla. The sum o
Blizzard [7]

We are given these three people age below:

  • Jim's age
  • Carla's age
  • Tomy's age

We define the age of Jim as any variable, because the problem doesn't give any specific age. I will define Jim's age as x.

  • Jim's age = x

Next, Carla is 5 years older than Jim. That means if Carla is 5 years older, her age would be x+5.

  • Carla's age = x+5

Then Tomy is 6 years older than Carla. That means the age would be 6+(x+5).

  • Tomy's age = 6+(x+5)

The sum of their three ages is 31 years old. That means we add all these ages and equal to 31.

\large{x + x + 5 + 6 + x + 5 = 31}

Combine like terms and solve for x.

\large{3x + 16 = 31}  \\  \large{3x = 31 - 16} \\  \large{3x = 15} \\  \large{x = 5}

Then we substitute the value of x in ages to find these three people ages.

  • Jim's age = x = 5
  • Carla's age = x+5 = 5+5 = 10
  • Tomy's age = 6+(x+5) = 6+(5+5) = 6+10 = 16.

Answer

  • Jim's age = 5
  • Carla's age = 10
  • Tomy's age = 16
4 0
2 years ago
Solve x^3-7x^2+7x+15​
ruslelena [56]

Step-by-step explanation:

\underline{\textsf{Given:}}

Given:

\mathsf{Polynomial\;is\;x^3+7x^2+7x-15}Polynomialisx

3

+7x

2

+7x−15

\underline{\textsf{To find:}}

To find:

\mathsf{Factors\;of\;x^3+7x^2+7x-15}Factorsofx

3

+7x

2

+7x−15

\underline{\textsf{Solution:}}

Solution:

\textsf{Factor theorem:}Factor theorem:

\boxed{\mathsf{(x-a)\;is\;a\;factor\;P(x)\;\iff\;P(a)=0}}

(x−a)isafactorP(x)⟺P(a)=0

\mathsf{Let\;P(x)=x^3+7x^2+7x-15}LetP(x)=x

3

+7x

2

+7x−15

\mathsf{Sum\;of\;the\;coefficients=1+7+7-15=0}Sumofthecoefficients=1+7+7−15=0

\therefore\mathsf{(x-1)\;is\;a\;factor\;of\;P(x)}∴(x−1)isafactorofP(x)

\mathsf{When\;x=-3}Whenx=−3

\mathsf{P(-3)=(-3)^3+7(-3)^2+7(-3)-15}P(−3)=(−3)

3

+7(−3)

2

+7(−3)−15

\mathsf{P(-3)=-27+63-21-15}P(−3)=−27+63−21−15

\mathsf{P(-3)=63-63}P(−3)=63−63

\mathsf{P(-3)=0}P(−3)=0

\therefore\mathsf{(x+3)\;is\;a\;factor}∴(x+3)isafactor

\mathsf{When\;x=-5}Whenx=−5

\mathsf{P(-5)=(-5)^3+7(-5)^2+7(-5)-15}P(−5)=(−5)

3

+7(−5)

2

+7(−5)−15

\mathsf{P(-5)=-125+175-35-15}P(−5)=−125+175−35−15

\mathsf{P(-5)=175-175}P(−5)=175−175

\mathsf{P(-5)=0}P(−5)=0

\therefore\mathsf{(x+5)\;is\;a\;factor}∴(x+5)isafactor

\underline{\textsf{Answer:}}

Answer:

\mathsf{x^3+7x^2+7x-15=(x-1)(x+3)(x+5)}x

3

+7x

2

+7x−15=(x−1)(x+3)(x+5)

\underline{\textsf{Find more:}}

Find more:

6 0
3 years ago
Splitting the middle term 2x^2-9x+4
DiKsa [7]
(2x-1)(x-4)
Hereeeeeeeee
8 0
3 years ago
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