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3 years ago

HELP PLEASE What is the expression in radical form?

Mathematics

1 answer:

IgorLugansk [536]3 years ago

6 0

Answer:

Step-by-step explanation:

$(2x^3y^4)^{\frac{3}{7}}=\sqrt[7]{(2x^3y^$)^3} =\sqrt[7]{8x^9y^3}$

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I have 5 minutes to put the answer in

Sholpan [36]

Answer:

-8

Step-by-step explanation:

Y=mx+b, m=slope

in this case -8 is the m

8 0

2 years ago

Read 2 more answers

Which equations match the graph?

spayn [35]

Answer:

The correct answer is B

Step-by-step explanation:

View attachments.

Use symbolab to compare the equations :)

Hope this helps XD

5 0

3 years ago

3. Solve each equation, and check your solution.

Alisiya [41]

1) 2m - 16 = 2m + 4

2m - 2m = 4 + 16

0 = 20 (no solution)

2) -4(r + 2) = 4(2 - 2r)

-(r + 2) = 2 - 2r

-r - 2 = 2 - 2r

-r + 2r = 2 + 2

r = 4

3) 12(5 + 2y) = 4y - (6 - 9y)

60 + 24y = 4y - 6 + 9y

60 + 24y = 13y - 6

24y - 13y = -6 - 60

11y = -66

y = -6

7 0

3 years ago

Right answer no lin or bot

kvv77 [185]

Answer:

$2\frac{9}{10} or\frac{29}{10}$

Step-by-step explanation:

Hope this helps! Have a great day ahead. Happy halloween :) Stay Safe <33

8 0

2 years ago

Read 2 more answers

Write a quadratic function for each graph described.

user100 [1]

Answer:

$y=2x^2-\frac{4}{3}x-\frac{10}{3}$

Step-by-step explanation:

we know that

The roots of the quadratic function (x-intercepts) are

x=-1 and x=5/3

we can write the equation of the parabola as

$y=a(x+1)(x-\frac{5}{3})$

where

a is a coefficient

Remember that

The parabola pass through the point (5,40)

substitute the value of x and the value of y of the ordered pair in the quadratic equation and solve for a

x=5, y=40

$40=a(5+1)(5-\frac{5}{3})$

$40=a(6)(\frac{10}{3})$

$40=20a\\a=2$

substitute

$y=2(x+1)(x-\frac{5}{3})$

apply distributive property

$y=2(x^2-\frac{5}{3}x+x-\frac{5}{3})\\\\y=2(x^2-\frac{2}{3}x-\frac{5}{3})\\\\y=2x^2-\frac{4}{3}x-\frac{10}{3}$

see the attached figure to better understand the problem

6 0

3 years ago