HELP PLEASE<br><br> What is the expression in radical form?

A Pew Internet poll asked cell phone owners about how they used their cell phones. One question asked whether or not during the

EastWind [94]

Answer:

a) $\hat p=\frac{471}{1024}=0.460$

The standard error is given by:

$SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156$

And the margin of error is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305$

b) The 99% confidence interval would be given by (0.429;0.491)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

Data given and notation

n=1024 represent the random sample taken

X=471 represent the people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

$\hat p=\frac{471}{1024}=0.460$ estimated proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

p= population proportion of people responded that they had used their cell phone while in a store within the last 30 days to call a friend or family member for advice about a purchase they were considering

Part a

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

The standard error is given by:

$SE= \sqrt{\frac{\hat p(1-\hat p)}{n}}=\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0156$

And the margin of error is given by:

$ME=z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}=1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.0305$

Part b

If we replace the values obtained we got:

$0.460-1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.429$

$0.460+1.96\sqrt{\frac{0.460(1-0.460)}{1024}}=0.491$

The 99% confidence interval would be given by (0.429;0.491)

8 0

3 years ago

Find the values of x and y.

ValentinkaMS [17]

Answer:

x=110° y=140°

Step-by-step explanation:

x=180°-70°

x=110°

y=x+30°

y=110°+30°

y=140°

3 0

3 years ago

Which of the following graphs represents a function

Nata [24]

Where are the graphs? a function is when every input is paired with exactly one output(every x value must have exactly 1 y value). the vertical line test helps determine a function, a vertical line can’t intersect a graph at more then one point, if it does intersect in more then 1 point then it’s not a function

7 0

3 years ago

Grace earns $7 for each car she washes. She always saves $25 of her weekly earnings.This week,she wants to have at least $65 in

Irina-Kira [14]

Answer:

she must wash 8 cars because 7 x 8 = 56 so yeah bye

Step-by-step explanation:

7 0

3 years ago

Write the equation for the line that goes through point (1, 1) with slope m = -9

DENIUS [597]

1) Since we have the slope, and one point we can find that linear equation using this point-slope formula. Plugging them we have:

$\begin{gathered} (y-y_0)=m(x-x_0) \\ y-1=-9(x-1) \\ y-1=-9x+9 \\ y=-9x+9+1 \\ y=-9x+10 \end{gathered}$

2) Note that we had to add 1 to both sides, to keep the "y "on the left.

3) Therefore, y=-9x+10 is the answer.

7 0

1 year ago

HELP PLEASE What is the expression in radical form?