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PtichkaEL [24]
3 years ago
13

it takes 18 3/8 inches of wood to make a frame for a small picture if Ms Jones has 108 inches of wood how many frames can she ma

ke

Mathematics
2 answers:
scZoUnD [109]3 years ago
6 0
It would make 5 complete frames, and about 8/10 of another frame.
108 / 18.375 = 5.8&*)&^&%*$*
I used a calculator.
You could keep adding 18 and 3/8 over and over again until you get right under 108 if you're good at math like me, but most people would have to add 18 and 3/8 separately.

Thanks, and if you liked my answer, please consider giving me the brainliest answer, because I need 5 of them to get to the next level.
Lady bird [3.3K]3 years ago
5 0
Namely, how many times does 18 and 3/8 go into 108?

\bf \cfrac{108}{18\frac{3}{8}}\implies \cfrac{108}{\frac{18\cdot 8+3}{8}}\implies \cfrac{108}{\frac{147}{8}}\implies \cfrac{\frac{108}{1}}{\frac{147}{8}}\implies \cfrac{108}{1}\cdot \cfrac{8}{147}
\\\\\\
\cfrac{36\cdot \underline{3}}{1}\cdot \cfrac{8}{\underline{3}\cdot 49}\implies \cfrac{288}{49}
\\\\\\
\textit{49 goes into 288 \underline{5 times}, with a \underline{remainder} of 43}\implies 5\frac{43}{49}
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prohojiy [21]
<span>2y = x + 3 then x = 2y - 3
5y = x - 7 then x = 5y + 7

so 
</span>2y - 3 = 5y + 7
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y = -10/3
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<span>2y = x + 3
</span>2 (-10/3) = x + 3
-20/3 - 3 =x
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or
x = -9 2/3

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3 years ago
Christopher works at the power plant for the southwest part of his home state. For peak operational performance, his department
Licemer1 [7]

Answer:

B) To maintain peak performance for every 50 generators, there are 10 inspectors.

Step-by-step explanation:

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4 inspectors for every 60 electricians. ⇒  60 Electricians : 4 Inspectors

Now, the number of generators the state has now = 50

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For, 3 electrician there  is 1 generator

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Also, for 60 Electrician there are 4 inspectors.    (2)

⇒From (1) and (2), we get:

For every 20 generators, there are 4 inspectors.

And, from what we have assumed  For every 50 generators, there are m inspectors.

So, by the RATIO OF PROPORTION:

\frac{20}{4}  = \frac{50}{m}\\ \implies  m = 50 \times\frac{4}{20}  = 10

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Hence, to maintain peak performance for every 50 generators, there are 10 inspectors.

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