Question

Christopher works at the power plant for the southwest part of his home state. For peak operational performance, his department

Answer 1

Answer:

B) To maintain peak performance for every 50 generators, there are 10 inspectors.

Step-by-step explanation:

For peak operational:

3 electricians for each generator.  ⇒  1 Generator : 3 Electricians

4 inspectors for every 60 electricians. ⇒  60 Electricians : 4 Inspectors

Now, the number of generators the state has now = 50

Let us assume the number of  inspectors  required by the power plant  = m

Now, from the given ratios:

For, 3 electrician there  is 1 generator

⇒ For, 3 x 20 Electrician  there is 1  x 20 Generators.

or, for 60 Electrician there are 20 Generators.   (1)

Also, for 60 Electrician there are 4 inspectors.    (2)

⇒From (1) and (2), we get:

For every 20 generators, there are 4 inspectors.

And, from what we have assumed  For every 50 generators, there are m inspectors.

So, by the RATIO OF PROPORTION:

$\frac{20}{4} = \frac{50}{m}\\ \implies m = 50 \times\frac{4}{20} = 10$

or, m = 10

Hence, to maintain peak performance for every 50 generators, there are 10 inspectors.