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3 years ago

5

Graph.......??????...........

1 answer:

QveST [7]3 years ago

4 0

graph b is the answer

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Write an equation to make the number "24" using all the numbers 5,4,2,2 and +, -, x and ÷.

Snezhnost [94]

Answer: See explanation

Step-by-step explanation:

We are given the numbers 5,4,2, and 2 and told to make an equation from it and get a final answer as 24. This will be:

= 5 × 4 + 2 + 2

= 20 + 2 + 2

= 24.

Since we have gotten a final answer of 24, the equation is solved.

8 0

2 years ago

(18 - ab) + 4b (if a = -2 and b = -5)

ivanzaharov [21]

Answer:

-12

Step-by-step explanation:

if a=-2 and b=-5

(18-(-2×-5))+4(-5)

(18-(10))-20

8-20

-12

just gotta plug in the given into the equation

5 0

3 years ago

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I am thinking of an animal whose name starts with the letter e. Guess the<br> animal.

laiz [17]

Answer:

elk

Step-by-step explanation:

4 0

3 years ago

Find the components of the vertical force Bold Upper FFequals=left angle 0 comma negative 10 right angle0,−10 in the directions

quester [9]

Solution :

Let $v_0$ be the unit vector in the direction parallel to the plane and let $F_1$ be the component of F in the direction of $v_0$ and $F_2$ be the component normal to $v_0$ .

Since, $|v_0| = 1,$

$(v_0)_x=\cos 60^\circ= \frac{1}{2}$

$(v_0)_y=\sin 60^\circ= \frac{\sqrt 3}{2}$

Therefore, $v_0 = \left$

From figure,

$|F_1|= |F| \cos 30^\circ = 10 \times \frac{\sqrt 3}{2} = 5 \sqrt3$

We know that the direction of $F_1$ is opposite of the direction of $v_0$ , so we have

$F_1 = -5\sqrt3 v_0$

$=-5\sqrt3 \left$

$= \left$

The unit vector in the direction normal to the plane, $v_1$ has components :

$(v_1)_x= \cos 30^\circ = \frac{\sqrt3}{2}$

$(v_1)_y= -\sin 30^\circ =- \frac{1}{2}$

Therefore, $v_1=\left< \frac{\sqrt3}{2}, -\frac{1}{2} \right>$

From figure,

$|F_2 | = |F| \sin 30^\circ = 10 \times \frac{1}{2} = 5$

∴ $F_2 = 5v_1 = 5 \left< \frac{\sqrt3}{2}, - \frac{1}{2} \right>$

$=\left$

Therefore,

$F_1+F_2 = \left< -\frac{5\sqrt3}{2}, -\frac{15}{2} \right> + \left< \frac{5 \sqrt3}{2}, -\frac{5}{2} \right>$

$= = F$

3 0

2 years ago

What is the equation for the points (-3,1) and (9,7)

Scorpion4ik [409]

Answer:

The equation of line with given points is 2Y - X - 5 = 0

Step-by-step explanation:

Given points are ( - 3 , 1) and (9 , 7)

Equation of line is y = mx +c

where m is the slop of line

Now m = $\frac{y2 - y1}{x2 - x1}$

Or, m = $\frac{7 - 1}{9 + 3}$

so, slop = $\frac{6}{12}$

∴ slop = $\frac{1}{2}$

Now the equation of line with points ( -3 , 1) and slop m is :

Y - y1 = m ( X - x1)

Or, Y - 1 = $\frac{1}{2}$ (X + 3)

Or, 2Y - X - 5 = 0

Hence The equation of line with given points is 2Y - X - 5 = 0 Answer

6 0

3 years ago