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klasskru [66]
3 years ago
8

Covert 3.92 into a mixed number in simplest form?

Mathematics
2 answers:
solong [7]3 years ago
5 0
3.92 = \frac{392}{100} \\ 
        = \frac{98}{25} Answer
12345 [234]3 years ago
3 0
3.92

= 1.00 + 1.00 + 1.00 + 0.92

= 100/100 + 100/100 + 100/100 + 92/100

= 300/100 + 92/100

= 392/100

-------------------------------------------------------

392/100 = 196/50 = 98/25
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Mole Conversion:<br> What is the mass of 3.13 x 1023 molecules of carbon dioxide?
4vir4ik [10]

Answer:

The mass of 3.13*10²³ molecules of carbon dioxide is 22.88 g.

Step-by-step explanation:

Avogadro's Number or Avogadro's Constant is the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole and it applies to any substance.

Then you can apply the following rule of three: if 6.023*10²³ molecules are present in 1 mole, 3.13*10²³ molecules are present in how many moles?

moles=\frac{3.13*10^{23}molecules*1 mole }{6.023*10^{23}molecules}

moles= 0.52

Since the molar mass of carbon dioxide is 44 g / mole, then the following rule of three can be applied: if there are 44 g in 1 mole, how much mass is there in 0.52 moles?

mass=\frac{0.52 moles*44 g}{1 mole}

mass= 22.88 g

<u><em>The mass of 3.13*10²³ molecules of carbon dioxide is 22.88 g.</em></u>

8 0
2 years ago
NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!!! THIS IS NOT A TEST OR AN ASSESSMENT!! Please help me with these math questions
Art [367]

Answer:

See below

Step-by-step explanation:

3. What are two ways that a vector can be represented?

Considering a vector \vec{v} in some vector space \mathbb R^n we have

\vec{v} = \langle a,b\rangle

This is the component form. I don't like that way. It is probably used in high school, but

\vec{v} =  \begin{pmatrix} a\\ b\\ \end{pmatrix}

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$\langle a,b\rangle := \sum_{i = 1}^n a_i b_i$

You can also write it using linear form such as \vec{v} = 2i+2j

4.

For this question, I think you meant

vectors

\vec{u_1} = (-8, 12)

\vec{u_2}  = (13, 15)

Once

\cos(\theta)=\dfrac{\vec{u_1} \cdot\vec{u_2}}{||\vec{u_1}||||\vec{u_2}||}

Considering that the dot product is

\vec{u_1}\cdot \vec{u_2} = (-8)\cdot 13 + 12\cdot 15 = -104+180= 76

and the norm of \vec{u_1} is ||\vec{u_1}|| = \sqrt{(-8)^2 + 12^2} = \sqrt{64 + 144}= \sqrt{208}

and the norm of \vec{u_2} is ||\vec{u_2}|| = \sqrt{13^2 + 15^2} = \sqrt{169 + 225}= \sqrt{394}

Thus,

\cos(\theta)=\dfrac{76}{\sqrt{208} \sqrt{394}} = \dfrac{19}{\sqrt{13}\sqrt{394}}=\dfrac{19}{\sqrt{5122}}

\therefore \theta = \arccos \left(\dfrac{19}{\sqrt{5122}} \right)

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Step-by-step explanation:

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3. After, you add 14 to your precious answer (-14) then subtract 4.

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