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3 years ago

How to round 43 to the nearest ten

2 answers:

5 0

So,

We need to round 43 to the nearest ten.

Look at the number in the one's place. If the number is greater than or equal to 5, round up. If the number is less than 5, round down.

43 rounded to the nearest ten is 40.

mixer [17]3 years ago

4 0

The answer is 40.
Steps:
1. Look at the tens place which has the number 4
2. Look at the number behind it
3. Since, the number is 3, you round down to 40
( if your number is less than 5, you round down)

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Without using logarithm tables, find the value of x given that: 2log2/3 = 1/2logx - log 18 + log 16

sweet-ann [11.9K]

Answer:

$x=\frac{1}{4}$

Step-by-step explanation:

Given:

$2log(\frac{2}{3})=\frac{1}{2}log(x)-log(18)+log(16)$

Use the Power Rule Law:

$log(\frac{2}{3}^2)=log(x^{1/2})+log(16)-log(18)$

Use the Quotient Rule Law:

$log(\frac{4}{9})=log(\sqrt{x})+log(\frac{16}{18})$

Use the Product Rule Law:

$log(\frac{4}{9})=log(\frac{16\sqrt{x}}{18})$

Simplify:

$log(\frac{4}{9})=log(\frac{8\sqrt{x}}{9})$

$\frac{4}{9}=\frac{8\sqrt{x}}{9}$

$4=8\sqrt{x}$

$\frac{4}{8}=\sqrt{x}$

$\frac{1}{2}=\sqrt{x}$

$\frac{1}{4}=x$

5 0

2 years ago

A rectangle has a length of 12 and a width that is half the length. What is the area?

Basile [38]

Answer:

Area = length x width

width = 1/2 length = 12/2 = 6 = width

area = 6x 12 = 72

Hope that answers your question

don't hesitate to comment if you are confused about something

Step-by-step explanation:

3 0

2 years ago

Solve for x in terms of y: 5y = 3x + 2

Ipatiy [6.2K]

Answer:

3/5

Step-by-step explanation:y

put in slop intersect form y=3/5x + 2/5 = 3/5

4 0

3 years ago

In ΔABC, if AB = 14 and BC = 9, AC may be equal to

Pie

Answer:

AC could be any number of these numbers 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22

Step-by-step explanation:

There is a fact in any triangle:

The length of any side of a triangle must be greater than the difference of the lengths of the other two sides and smaller than the sum of the lengths of the other two sides

If the lengths of the three sides of a triangle are a , b and c, then

a - b < c < a + b
b - c < a < b + c
a - c < b < a + c

In Δ ABC:

→ (BC) - (AC) < AB < (BC) + (AC)

→ (AB) - (AC) < BC < (AB) + (AC)

→ (AB) - (BC) < AC < (AB) + (BC)

∵ AB = 14 units

∵ BC = 9 units

- Find the sum and difference of them

∵ AB - BC = 14 - 9

∴ AB - BC = 5

∵ AB + BC = 14 + 9

∴ AB + BC = 23

- That means the length of AC could be any integer greater

than 5 and smaller than 23

∴ 5 < AC < 23

AC could be any number of these numbers 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 21, 22

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2 years ago