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Ainat [17]
3 years ago
13

PLEASEPLEASE ANSWER

Mathematics
1 answer:
IRINA_888 [86]3 years ago
3 0

Answer:

x = 7

Step-by-step explanation:

A triangle's total interior angle measurement will equal 180°.

Set all measurements equal to 180:

(82) + (9x - 6) + (6x - 1) = 180

Simplify. Combine like terms:

(82 - 6 - 1) + (9x + 6x) = 180

(82 - 7) + (15x) = 180

(75) + 15x = 180

Next, isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

PEMDAS is the order of operation, and stands for:

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

~

First, Subtract 75 from both sides of the equation:

15x + 75 = 180

15x + 75 (-75) = 180 (-75)

15x = 180 - 75

15x = 105

Next, divide 15 from both sides of the equation:

(15x)/15 = (105)/15

x = 105/15

x = 7

7 is your value for x.

~

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3 years ago
How would the expression x^3-8 be written using difference of cubes
ludmilkaskok [199]

we can use formula

a^3-b^3=(a-b)(a^2+ab+b^2)

we can compare

we get

a=x

b=2

now, we can plug that in formula

and we get

x^3-2^3=(x-2)(x^2+2x+2^2)

now, we can simplify it

x^3-8=(x-2)(x^2+2x+4)...........Answer

4 0
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PLEASE HELP ASAP!! 15 points
Talja [164]

Answer:

The asymptote is y = -2


3 0
3 years ago
PLEASE HELPPP ASAPPPPPPP
Mila [183]
You basically have to find the slope, to find the average rate of change, because finding the slope and finding the average rate of change is basically the same thing.

Here's the formula : \frac{y(2) - y(1)}{x(2) - x(1)}

So here, all you'd have to do is simply pick two points, and insert them into this formula. Say you take the points (-2, -2) and (0,-3). You would start from the y-intercept of the second point, and insert them all into the formula.

\frac{-3 - (-2)}{0-(-2)} which would turn into \frac{-1}{2}. And so since you want a good, stable number, and not just a fraction, you would divide -1 and 2, and the average rate of change would be -0.50.

AVERAGE RATE OF CHANGE : -0.50
5 0
3 years ago
Evaluate the function f(x) at the given numbers (correct to six decimal places).
3241004551 [841]

Answer:

The function f(x) = \frac{x^{2}-4\cdot x}{x^{2}-16} has the following set of solutions:

f(4.1) = 0.506173, f(4.05) = 0.503106, f(4.01) = 0.500624, f(4.001) = 0.500062, f(4.0001) = 0.500006, f(4.0001) = 0.500006

f(3.9) = 0.493671, f(3.95) = 0.496855, f(3.99) = 0.499374, f(3.999) = 0.499937, f(3.9999) = 0.499994

Step-by-step explanation:

Let be f(x) = \frac{x^{2}-4\cdot x}{x^{2}-16}, we proceed to simplify the expression by Algebraic means:

1) \frac{x^{2}-4\cdot x}{x^{2}-16} Given

2) \frac{x\cdot (x-4)}{(x-4)\cdot (x+4)} Associative, commutative and distributive properties/a^{2}-b^{2} = (a+b)\cdot (a - b)

3) \frac{x}{x + 4} Commutative, associative and modulative properties/Existence of multiplicative inverse/Result

Now we evaluate the function for each value:

x = 4.1

f(4.1) = \frac{4.1}{4.1+4}

f(4.1) = 0.506173

x = 4.05

f(4.05)  = \frac{4.05}{4.05 + 4}

f(4.05) = 0.503106

x = 4.01

f(4.01) = \frac{4.01}{4.01 + 4}

f(4.01) = 0.500624

x = 4.001

f(4.001) = \frac{4.001}{4.001+4}

f(4.001) = 0.500062

x = 4.0001

f(4.0001) = \frac{4.0001}{4.0001 + 4}

f(4.0001) = 0.500006

x = 3.9

f(3.9) = \frac{3.9}{3.9+4}

f(3.9) = 0.493671

x = 3.95

f(3.95) = \frac{3.95}{3.95+4}

f(3.95) = 0.496855

x = 3.99

f(3.99) = \frac{3.99}{3.99+4}

f(3.99) = 0.499374

x = 3.999

f(3.999) = \frac{3.999}{3.999 + 4}

f(3.999) = 0.499937

x = 3.9999

f(3.9999) = \frac{3.9999}{3.9999 + 4}

f(3.9999) = 0.499994

4 0
3 years ago
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