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3 years ago

How is subtracting a

Mathematics

2 answers:

Aleks [24]3 years ago

4 0

Because when you subtract a negative number the signs cancel out and become and addition problems

miskamm [114]3 years ago

4 0

When you subtract a negative number, the two negatives cancel out and become a positive so you end up adding the number instead, exactly like when you add a number like normal

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Troy's family is going to the beach for vacation. They plan to drive at the posted speed limit of 65 miles per hour and drive 5

Elena-2011 [213]

The answer is A) the number of miles

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2 years ago

WILL MARK BRAINLIEST!!! 70 POINTS!!! for real answers plz(●'◡'●)

Slav-nsk [51]

Answer:

In explanation ! :P

Step-by-step explanation:

Likes hamburgers and burritos : 39

Likes nothing : 33

Total missing : 205

Percentage who do like nothing : 16,09 %

Percentage who like all (without frequency table ) : 19,02 %

( without relative frequencies, sorry they don't let me :( : Is people who don't like burritos but likes hamburgers,they are the strongest )

I hope I helped you !^^

Sorry they don't let me do the frequency table ! :(

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3 years ago

The nurse reported that Tricia's daughter had gained 4.2 pounds

tino4ka555 [31]

31.6-4.2=27.4 at last visit

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2 years ago

How to convert 87 24/25 into a decimal

Anvisha [2.4K]

87 is a whole number and is the larger one so your answer is going to be 87 something. Decimals are always based on 100% so 25 x 4 = 100 as well as 24 x 4 is 96. This make it 87 and 96/100. In decimal form, The number would look like this : 87.96

5 0

3 years ago

The estimated value of the integral from 0 to 2 of x cubed dx , using the trapezoidal rule with 4 trapezoids is

bulgar [2K]

The integral is approximated by the sum,

$\displaystyle\int_0^2f(x)\,\mathrm dx\approx\sum_{n=0}^4\frac12\times\frac{f(x_n)+f(x_{n+1})}2=\frac14\sum_{n=0}^3(f(x_n)+f(x_{n+1}))$

where $f(x)=x^3$ and $x_n=\dfrac12n$ , giving you

$\displaystyle\frac14\sum_{n=0}^3\bigg(\left(\frac n2\right)^3+\left(\frac{n+1}2\right)^3\bigg)$
$\displaystyle\frac1{32}\sum_{n=0}^3(n^3+(n+1)^3)$
$\displaystyle\frac1{32}\sum_{n=0}^3(2n^3+3n^2+3n+1)$

Faulhaber's formulas make short work of computing the sum. You have

$\displaystyle\sum_{n=0}^k1=k+1$
$\displaystyle\sum_{n=0}^kn=\frac{k(k+1)}2$
$\displaystyle\sum_{n=0}^kn^2=\frac{k(k+1)(2k+1)}6$
$\displaystyle\sum_{n=0}^kn^3=\frac{k^2(k+1)^2}4$

which gives

$\displaystyle\frac1{16}\sum_{n=0}^3n^3+\frac3{32}\sum_{n=0}^3n^2+\frac3{32}\sum_{n=0}^3n+\frac1{32}\sum_{n=0}^31$
$\displaystyle\frac{36}{16}+\frac{42}{32}+\frac{18}{32}+\frac4{32}$
$\implies\displaystyle\int_0^2x^3\,\mathrm dx\approx\frac{17}4=4.25$

4 0

3 years ago