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alex41 [277]
3 years ago
14

What is the derivative of x^3

Mathematics
1 answer:
wolverine [178]3 years ago
8 0
The derivative here is what you get when you bring the exponent down as the coefficient (i.e. the 3) and subtract the exponent by 1. In this case, the answer will be 3x^2.
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Please help I need help with this badly asap !
evablogger [386]

Answer:

The third option

Step-by-step explanation:

It perfectly represents -24/3.

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3(x + 7) + 2(-x + 4) + 5x
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Answer:

x=9

Step-by-step explanation:

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Leni [432]

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Step-by-step explanation:

57.6

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Read 2 more answers
6) Two boats set off from X at the same
lord [1]

Answer:

The distance between the two boats after 2.5 hours is 57 m.

Step-by-step explanation:

The distance covered by each boat after 2.5 hours are:

speed = \frac{distance}{time}

distance = speed x time

For boat A, speed = 14 km/h and time = 2.5 hrs.

So that,

distance = 14 x 2.5

              = 35 km

For boat B, speed = 18 km/h and time = 2.5 hrs.

So that,

distance = 18 x 2.5

              = 45 km

The distance between the two boats after travelling 2.5 hours can be determined by applying the cosine rule. Let the distance be represented by x, so that:

a^{2} = b^{2} + c^{2} - 2bc Cos A

x^{2} = 45^{2} + 35^{2} - 2(45 x 35) Cos 90^{o}

   = 2025 + 1225 - 3150 (0)

   = 3250

x = \sqrt{3250}

  = 57.0088

x = 57.0 m

The distance between the two boats after 2.5 hours is 57 m.

4 0
3 years ago
The planet venus is on average 2.5x10^7 kilometers from earth. The planet mars is on average 2.25x10^8 kilometers from earth. Wh
umka21 [38]

Answer:

The average distance from venus to mars is 2.5x10⁸ kilometers.

Step-by-step explanation:

We know:

d₁: average distance between venus and earth = 2.5x10⁷ km

d₂: average distance between mars and earth = 2.25x10⁸ km

We can find the average distance from venus to mars as follows:

d_{t} = d_{1} + d_{2}

First, we need to equal the base power 10 so we can sum both distances:

2.25 \cdot 10^{8} = 2.25 \cdot 10^{7} \times 10 = 22.5 \cdot 10^{7} km      

Now, average distance:

d_{t} = 2.5 \cdot 10^{7} + 22.5 \cdot 10^{7} = (2.5 + 22.5) \cdot 10^{7} = 25 \cdot 10^{7} km = 2.5 \cdot 10^{8} km

Therefore, the average distance from venus to mars is 2.5x10⁸ kilometers.

I hope it helps you!              

6 0
3 years ago
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