Question

In a certain school, 17 percent of the student are enrolled in a psychology course, 28 percent are enrolled in a foreign language course, and 32 percent are enrolled in either a psychology course or a foreign language course or both. what is the probability that a student chosen at random from this school will be enrolled in both a foreign language course and a psychology course?

Answer 1

The probability that a student chosen at random from this school will be enrolled in both a foreign language course and a psychology course can be solve by: P = F x Psy Where F is the fraction of foreign language Psy is fraction in psychology   P = 0.28 x 0.17 P = 0.0476 is the probability 

Answer 2

Answer:

The probability that a student chosen at random from this school will be enrolled in both a foreign language course and a psychology course are 0.13

Step-by-step explanation:

Consider the provided information.

17 percent of the student are enrolled in a psychology course.

Let P(A) represents the student enrolled in psychology course.

Thus. P(A)=17%=0.17

28 percent are enrolled in a foreign language course.

Let P(B) represents the student enrolled in foreign language course.

Thus. P(B)=28%=0.28

32 percent are enrolled in either a psychology course or a foreign language course or both.

That means P(A∪B) = 32% = 0.32

We need to find the probability that a student chosen at random from this school will be enrolled in both a foreign language course and a psychology course.

That means we need to find P(A∩B).

P(A∪B) = P(A)+P(B)-P(A∩B)

0.32 = 0.17 + 0.28 - P(A∩B)

0.32 = 0.45 - P(A∩B)

P(A∩B) = 0.13

Hence, the probability that a student chosen at random from this school will be enrolled in both a foreign language course and a psychology course are 0.13