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SOVA2 [1]
3 years ago
9

One number is 4 more than another, and their sum is 60. What is the smaller number?

Mathematics
1 answer:
ivanzaharov [21]3 years ago
5 0
According to your question, there are 2 unknown numbers mentioned. Let the 2 unknown numbers be represented by the variables x & y, then x is considered to be one of the numbers being more than y by the addition of 4, .ie. x = 4 + y --- (1) The sum of the 2 numbers is 60, i.e. x + y = 60 --- (2) To find the smaller number, we solve eqn (1) & (2) using the concept of substitution, i.e. substitute 4 + y for x in eqn (2), i.e. 4 + y + y = 60 4 + 2y = 60 2y = 60 - 4 2y = 56 y = 28 ...Ans. Recall that x is more than y by 4, then 28 is the smaller number.
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andrezito [222]
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4 years ago
Rina is 6x+3/8 feet tall and Ryan is 5x+1/8 feet tall. How much taller is Rina than Ryan
worty [1.4K]

Answer:

Rina is 1/4 feet taller than Ryan

Step-by-step explanation:

(height of Rina)-(height of Ryan)

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x+3-1/8

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8 0
4 years ago
A cylindrical tank is half-full of oil. The cylinder has a base radius of 100 cm. The height of the cylinder is 250 cm. How many
lbvjy [14]
V=hpir²


1/2 full

Vcylinderthisone=(1/2)hpir^2
given
h=250
r=100

so

V=(1/2)(250)pi(100)²
V=125pi10000
V=1250000pi
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7 0
4 years ago
Read 2 more answers
If the set U = {all positive integers} and set A = {x|x ∈ U and x is an odd positive integer}, which describes the complement of
dlinn [17]

Answer: Choice D) set of even integers

=======================================================

Explanation:

U = universal set = {all positive integers} = {1, 2, 3, 4, 5, ...}

A = {stuff in set U that is odd} = {1, 3, 5, 7, 9, ...}

A^c = {stuff in set U but NOT from set A} = {2, 4, 6, 8, ...}

A^c = {set of even numbers from set U}

In set theory, the complement is simply the complete opposite. If the number 7 is found in set A for instance, then 7 is not going to live in the complement A^c

The opposite of the odd numbers is the set of even numbers.

Therefore, we go for <u>choice D</u> as our final answer.

Side note: if we union set A with its complement A^c then we get the universal set as a result. A \cup A^c = \text{universal set} = \text{set of all positive integers}

5 0
2 years ago
What is the solution to –122 &lt; –3(–2 – 8x) – 8x?
Soloha48 [4]
<span>–122 < –3(–2 – 8x) – 8x
-122< 6 + 24x - 8x
-122 < 6 + 16x
-122 - 6 < 16x
-128<16x
-128/16<x
-8<x
x>-8
answer is </span>B. x > –8
6 0
3 years ago
Read 2 more answers
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