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3 years ago

One number is 4 more than another, and their sum is 60. What is the smaller number?

1 answer:

5 0

According to your question, there are 2 unknown numbers mentioned. Let the 2 unknown numbers be represented by the variables x & y, then x is considered to be one of the numbers being more than y by the addition of 4, .ie. x = 4 + y --- (1) The sum of the 2 numbers is 60, i.e. x + y = 60 --- (2) To find the smaller number, we solve eqn (1) & (2) using the concept of substitution, i.e. substitute 4 + y for x in eqn (2), i.e. 4 + y + y = 60 4 + 2y = 60 2y = 60 - 4 2y = 56 y = 28 ...Ans. Recall that x is more than y by 4, then 28 is the smaller number.

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$=\dfrac{8!}{(8-4)!4!}\times\dfrac{9!}{(9-5)!5!}\times\dfrac{9!}{(9-2)!2!}\times\dfrac{7!}{3!(7-3)!}\\\\ =\dfrac{8\times7\times6\times5\times4!}{4!4!}\times\dfrac{9\times8\times7\times6\times5!}{4!5!}\times\dfrac{9\times8\times7!}{7!2!}\times\dfrac{7\times6\times5\times4!}{3!4!}\\\\=11113200$

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