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2 years ago

HELP DUE SUPER SOON!!

Mathematics

1 answer:

kow [346]2 years ago

6 0

Answer:

2022 students

Step-by-step explanation:

Since 18 out of 270 students speak three or more languages, a prediction would be 30,330 x 18/270 = 2,022 students

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Vladimir79 [104]

Answer:

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A pound of grapes costs $2.49. Lucas bought two pounds of grapes. He gave the clerk a $10.00 bill. How much change did Lucas get

GaryK [48]

Answer:

$5.02

Step-by-step explanation:

$2.49 × 2 = $4.98

$10 - $4.98 = $5.02

7 0

2 years ago

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is:

$(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})$

$(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]$

$(x,y) = (10.452, 34.531)\,[km]$

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

$\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}$

$\theta \approx 16.840^{\circ}$

And the distance from the camp is calculated by the Pythagorean Theorem:

$r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}$

$r = 36.078\,km$

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0

3 years ago

Which relation is a function?

NARA [144]

Answer:

A function means that we get one input and one output. In this example that means for every x-value that we have, we only have one y-value.

Looking at the first option, we can see that there is no x-value that has more than one y-value which means that it is a function.

The rest of the options are seen with at least two values for one x-value in one of the points. Therefore, they wouldn't be considered a function leaving us with only option A as the solution.

8 0

1 year ago

Can someone help me with this please

Xelga [282]

Answer:

9,17

Step-by-step explanation:

larger no=8+smaller no

larger no+ smaller no= 26

::8+s(larger no from equation 1 )+s=26

*2s=18

*s=9

3 0

3 years ago