Let's name the seats 1 through 120.
Occupy seat 2.
Leave 2 empty seats. You can't leave 3 empty seats because then the middle seat of the three empty seats is not adjacent to an occupied seat. You can leave only 2 seats empty. Seats 3 and 4 are empty.
Occupy seat 5.
Leave 2 empty seats. Seats 6 and 7 are empty.
Keep on going like this to the end, occupying 1 seat and leaving 2 seats empty.
Now we need to find the number of occupied seats.
Think of the entire row being divided into groups of 3 seats.
The middle seat of each group is occupied.
Since there are 120 seats in the row, there are 40 groups of 3 seats whose middle seat is occupied. There are 40 middle seats, so there are 40 occupied seats.
Answer: 40 seats
Answer:
7 positive integer solutions
Step-by-step explanation:
3(x-5)≤7
Distribute
3x - 15 ≤7
Add 15 to each side
3x-15+15≤7+15
3x≤22
Divide by 3
3x/3 ≤22/3
x≤7 1/3
Positive integer solutions
1,2,3,4,5,6,7 = 7
0 is neither positive nor negative
Hi :)
Dont spazm to much :D
M=2 do need a step by step explanation?
