Answer:
perimeter of a square is l+l+l+l
16+16+16+16=64
<h3><u>The first number, x, is equal to 33.</u></h3><h3><u>The second number, y, is equal to 23.</u></h3><h3><u>The third number, z, is equal to 46.</u></h3>
x + y + z = 102
z = 2y
x = 10 + y
Because we have values of x and z, we can plug them into the original equation to solve for y.
10 + y + y + 2y = 102
Combine like terms.
4y + 10 = 102
Subtract 10 from both sides.
4y = 92
Divide both sides by 4.
y = 23
Now that we have a value for y, we can find the value of x and z.
z = 2(23)
z = 46
x = 10 + 23
x = 33
The answer is C, eighty four combinations
Answer: you should study, plus give me brainliest please. lol
Step-by-step explanation:
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