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VMariaS [17]
3 years ago
15

In ΔPQR, find the measure of ∡ P. (4 points)

Mathematics
2 answers:
Alexus [3.1K]3 years ago
8 0
WHat are the choices

andrew11 [14]3 years ago
8 0
You do 180-90-57 and is equals 33
I hope this helps
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Quadrilateral RSTU is a parallelogram. What must be the value of x?
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I set x-3 and 3x-13 equal to each other and then got x equal to 5. So, I believe the correct answer would be C.) 5
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Bishon needs to sell at least 0.3 of his collection of sports cards to
diamong [38]

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Find the slope of the line through the<br> given points: (2,6) &amp; (5, 6)
snow_tiger [21]

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3 years ago
Is 5 3/8 greater than 5 4/10
Lostsunrise [7]

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Step-by-step explanation:

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4 0
3 years ago
A videotape store has an average weekly gross of $1,158 with a standard deviation of $120. Let x be the store's gross during a r
statuscvo [17]

Answer:

The number of standard deviations from $1,158 to $1,360 is 1.68.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 1158, \sigma = 120

The number of standard deviations from $1,158 to $1,360 is:

This is Z when X = 1360. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1360 - 1158}{120}

Z = 1.68

The number of standard deviations from $1,158 to $1,360 is 1.68.

3 0
3 years ago
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