Answer:
The amount of weight he has lost in 3 months is 1.215 stone or 1 stone 3 pounds
Step-by-step explanation:
From the above question, we are to calculate the amount of weight he has lost in three months
1 stone = 14 pounds
Let's convert all the weight lost to stone
At the start of the diet keirin weighted 14 stone 13 pounds
14 pounds = 1 stone
13 pounds = x
Cross Multiply
14x = 13
x = 13/14
x = 0.9285714286 stone
Approximately = 0.929 stone
Hence:
14 stone 13 pounds = 14 + 0.929 = 14.929 stone
Three months later he weighted 13 stone 10 pounds
14 pounds = 1 stone
10pounds = x
Cross Multiply
14x = 10
x = 10/14
x = 0.7142857143 stone
Approximately = 0.714 stone
Hence:
13 stone 10 pounds = 13 + 0.714 = 13.714 stone
The amount of weight he has lost is calculated as:
14.929 stone - 13.714 stone = 1.215 stone or 1 stone 3 pounds
Answer:
3.28ft
Step-by-step explanation:
Rectangular Prism Formula:
l*w*d = v
(plug in values)
2.6*1.4*d=11.94
3.64*d=11.94
d = 3.28ft
Answer:
cos
(
390
)
−
4
cot
(
−
45
)
sin
(
330
)
Step-by-step explanation:
Answer:
<h3>Princeton Florist</h3>
Let the total charge is y, the number of small arrangements is x.
<u>Total charge will be:</u>
<h3>Chad's Flowers</h3>
<u>Total charge will be:</u>
<u>Since the total charge is same in both shops, we have:</u>
<u>Solve for x:</u>
- 17x - 13x = 47 - 35
- 4x = 12
- x = 3
<u>Total cost is:</u>
<u>Small arrangements</u> = 3, <u>cost </u>= $86
The figure showing the construction is given below.
Steps for the construction of a circle through three points not on a straight line are as follows:
1. To create two lines, connect the points.
2. Create the line's perpendicular bisector.
3. Create the opposite line's perpendicular bisector.
4. The circle's center is where they intersect.
5. Draw your circle by placing the compass on the center point and adjusting its length to reach any point.
What happens if the points are parallel?
The circle traveling through all three points will have an infinite radius if the three points are collinear, or all situated on a straight line. Therefore, a practical circle cannot traverse three collinear locations. The two radii would be parallel and would never come together at a center if you tried the construction. We may claim that they do cross mathematically but at infinity.
Hence, after following the steps we obtain the circle.
Learn more about constructions here-
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