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3 years ago

I need help understanding it. The notes my teacher gave me aren't helping

Mathematics

2 answers:

Ierofanga [76]3 years ago

6 0

Because this is x^2 it will be a parabola. The easiest way to do this (when given in standard form) is to go to your table function on your graphing calculator. You can tell what the vertex is because the y value will repeat (1, 0, 1).

So here is some of the table

0 9
1 4
2 1
3 0
4 1
5 4
6 9
7 16

So first plot the vertex (4,1) and then plot some of the other points on the graph and connect the dots.

Colt1911 [192]3 years ago

5 0

I believe you go on the x-axis on -6 and go up to 9. I could never be certain for I just learned this but I believe that is what it is..

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Help please help I really need it

nalin [4]

Answer: x^2

Step-by-step explanation: x times x is x^2

3 0

2 years ago

Read 2 more answers

PLEASE HELP ITS DUE IN A FEW MINS

ioda

The correct answer is 6,8

6 0

2 years ago

Evaluate the surface integral ∫sf⋅ ds where f=⟨2x,−3z,3y⟩ and s is the part of the sphere x2 y2 z2=16 in the first octant, with

skad [1K]

Parameterize S by the vector function

$\vec s(u,v) = \left\langle 4 \cos(u) \sin(v), 4 \sin(u) \sin(v), 4 \cos(v) \right\rangle$

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.

Compute the outward-pointing normal vector to S :

$\vec n = \dfrac{\partial\vec s}{\partial v} \times \dfrac{\partial \vec s}{\partial u} = \left\langle 16 \cos(u) \sin^2(v), 16 \sin(u) \sin^2(v), 16 \cos(v) \sin(v) \right\rangle$

The integral of the field over S is then

$\displaystyle \iint_S \vec f \cdot d\vec s = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \vec f(\vec s) \cdot \vec n \, du \, dv$

$\displaystyle = \int_0^{\frac\pi2} \int_0^{\frac\pi2} \left\langle 8 \cos(u) \sin(v), -12 \cos(v), 12 \sin(u) \sin(v) \right\rangle \cdot \vec n \, du \, dv$

$\displaystyle = 128 \int_0^{\frac\pi2} \int_0^{\frac\pi2} \cos^2(u) \sin^3(v) \, du \, dv = \boxed{\frac{64\pi}3}$

8 0

2 years ago

Points (-5,-3) (-2,-2) (-4,-6) reflected over y=-x-1

Mars2501 [29]

Answer:

frfrfr

Step-by-step explanation:

8 0

3 years ago

The table shows a student's proof of the quotient rule for logarithms.

nikklg [1K]

Answer:

The error is at step (3) .

The correct step (3) will be,

$\log_{b}(\frac {b^{x}}{b^{y}})$

= $\log_{b}(b^{x - y})$ [by using the laws of indices]

All other steps are correct.

Step-by-step explanation:

The error is at the step (3) , because the student has tried to prove the quotient rule of logarithms by using the property i.e., 'The quotient rule of logarithm' itself , i.e. ,by assuming the property does hold before proving it. So, the proof is fallacious.

The correct step (3) will be,

$\log_{b}(\frac {b^{x}}{b^{y}})$

= $\log_{b}(b^{x - y})$ [by using the laws of indices]

All other steps are correct.

5 0

3 years ago