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3 years ago

I need help understanding it. The notes my teacher gave me aren't helping

Mathematics

2 answers:

Ierofanga [76]3 years ago

6 0

Because this is x^2 it will be a parabola. The easiest way to do this (when given in standard form) is to go to your table function on your graphing calculator. You can tell what the vertex is because the y value will repeat (1, 0, 1).

So here is some of the table

0 9
1 4
2 1
3 0
4 1
5 4
6 9
7 16

So first plot the vertex (4,1) and then plot some of the other points on the graph and connect the dots.

Colt1911 [192]3 years ago

5 0

I believe you go on the x-axis on -6 and go up to 9. I could never be certain for I just learned this but I believe that is what it is..

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Solve for x. (please help)

Goryan [66]

Answer:

x=55

(2x+15)+x=180

Then slove this equation

8 0

4 years ago

2. The following formula relates three quantities: Force (F), mass (m), and acceleration (a).

castortr0y [4]

Let

F--------> represent the force

m--------> represent the mass

a-------> represent the acceleration

we know that

The formula that relates three quantities: Force (F), mass (m), and acceleration (a) is equal to

$F=ma$

Part a) Solve this equation for a

$F=ma$

Divide both sides by the mass

$a=\frac{F}{m}$

therefore

the answer part a) is equal to

$a=\frac{F}{m}$

Part b) Let the force be 25 units and the mass be m = 10 units. What is the acceleration, a?

we know that

the formula of acceleration is equal to

$a=\frac{F}{m}$

in this problem

we have

$F=25\\m=10$

Substitute the values n the formula

$a=\frac{25}{10}$

$a=2.5$

therefore

the answer part b( is equal to

$a=2.5$

Part c) Let the force be F = 25 units and the acceleration be a = 5 units. What is the mass, m?

we know that

$F=ma$

Solve for m

Divide both sides by the acceleration

$m=\frac{F}{a}$

in this problem

we have

$F=25\\a=5$

Substitute the values n the formula

$m=\frac{25}{5}$

$m=5$

therefore

the answer Part c) is

$m=5$

5 0

4 years ago

Read 2 more answers

A particle is moving with the given data. Find the position of the particle. a(t)=10sin(t)+3cos(t) s(0)=0 s(2pi)=12

zubka84 [21]

$a(t)=10\sin t+3\cos t$

$v(t)=\displaystyle\int a(t)\,\mathrm dt$
$v(t)=\displaystyle\int(10\sin t+3\cos t)\,\mathrm dt$
$v(t)=-10\cos t+3\sin t+C_1$

$s(t)=\displaystyle\int v(t)\,\mathrm dt$
$s(t)=\displaystyle\int(-10\cos t+3\sin t+C_1)\,\mathrm dt$
$s(t)=-10\sin t-3\cos t+C_1t+C_2$

With the boundary conditions $s(0)=0$ and $s(2\pi)=12$ , we have

$\begin{cases}0=-3+C_2&s(0)=0\\12=-3+2\pi C_1+C_2&s(2\pi)=12\end{cases}\implies C_1=\dfrac6\pi,C_2=3$

so that the position of the particle is given by

$s(t)=-10\sin t-3\cos t+\dfrac{6t}\pi+3$

3 0

4 years ago

WILL GIVE BRAINLIEST!!!

Mice21 [21]

Answer:

6 total

3 positive 2 digit numbers: 17, 52, 87

3 negative 2 digit numbers: -18, -53,-88

Step-by-step explanation:

We are given

x ≡ 3(mod7), x ≡ 2(mod5) and we want x to be two digits long.

x ≡ 3(mod7) means x-3=7k and

x ≡ 2(mod5) means x-2=5m where k and m are integers.

We need to find an x that satisfies both.

So some multiples of 7 are 7,14,21,28,35,42,49,56,63,70,77,84,91,98

Some multiples or 5 are

5,10 15,20,25,30 35,40,45,45,50,55,60,65,70

Now add 3 to first list for x=7k+3

10,17,24,31,38,45,52,59,66,73,80,87,94,101

Now add 2 to second list for x=5m+2

7,12 17,22,27,32 37,42,47,52,57,62,67,72

We only want to look at 2 digit numbers... just need to expand second list more:

Now add 2 to second list for x=5m+2

7,12,17,22,27,32,37,42,47,52,57,62,67,72,77,82,87,92,97,

That's all we need.

So let's write our lists and see the common numbers in them:

List 1: 10,17,24,31,38,45,52,59,66,73,80,87,94,101

List 2:

7,12,17,22,27,32,37,42,47,52,57,62,67,72,77,82,87,92,97

Common numbers: 17, 52, 87

Considering negative numbers as well:

x=7k+3:

3, -4, -11, -18, -25, -32,-39, -46, -53, -60, -67, -74, -81, -88, -95

x=5m+2:

2,-3,-8,-13,-18,-23,-28,-33,-38,-43,-48,-53,-58,-63,-68,-73,-78,-83,-88,-93,-98

Common 2digit numbers:

-18, -53,-88

7 0

3 years ago

1/6 - 2/3m >= 1/4 Algebra

siniylev [52]

thye awser should be m<-1/8

3 0

4 years ago