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2 years ago

I need help?? I don’t understand thanks!!

Mathematics

1 answer:

kondaur [170]2 years ago

8 0

Answer:

Step-by-step explanation:

What is the highest (greatest number) value that this graph goes to on your picture? We can see it is 9.

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X+3y=3<br> 2x-4y=6<br><br> solve the equations

Gelneren [198K]

Subtract the second equation from double the first equation:

2x+6y-2x-(-4y)=0

10y=0

Therefore, y=0. Substituting this into the first equation, we see that:

x+3(0)=3

x=3

Therefore, x=3. The solution to this system is x=3, y=0, or (3, 0).

4 0

3 years ago

Read 2 more answers

Write a subtraction fact with the same difference as 16-7?

Alona [7]

So, this is asking for any number that subtracts to = 16-7

Well, 16-7= 9 so use any two numbers that would subtract to equal 9

Like so:

11-2=9
18-9=9
34-25=9
-2-11=9
Etc....

Hope this helps! :)

7 0

3 years ago

Read 2 more answers

A rectangle is 25 in. long and 13 in. wide. What is the area of the rectangle? Enter your answer in the box as a fraction in sim

Anarel [89]

I hope this helps you

Area=length ×width

Area=25×13

Area =325

6 0

3 years ago

An insurance company selected a random sample of 500 clients under 18 years of age and found that 180 of them had had an acciden

Butoxors [25]

Answer:

a) The pooled proportion is p=0.3.

b) P-value = 0.000078

c) Lower bound = 0.0556

d) Upper bound = 0.1644

Step-by-step explanation:

This is a hypothesis test for the difference between proportions.

The claim is that the accident proportions differ between the two age groups .

Then, the null and alternative hypothesis are:

$H_0: \pi_1-\pi_2=0\\\\H_a:\pi_1-\pi_2\neq 0$

The significance level is 0.05.

The sample 1, of size n1=500 has a proportion of p1=0.36.

$p_1=X_1/n_1=180/500=0.36$

The sample 2, of size n2=600 has a proportion of p2=0.25.

$p_1=X_1/n_1=150/600=0.25$ .

The difference between proportions is (p1-p2)=0.11.

$p_d=p_1-p_2=0.36-0.25=0.11$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{180+150}{500+600}=\dfrac{330}{1100}=0.3$

The standard error for the difference between proportions can now be calculated as:

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.3*0.7}{500}+\dfrac{0.3*0.7}{600}}\\\\\\s_{p1-p2}=\sqrt{0.00042+0.00035}=\sqrt{0.00077}=0.0277$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.11-0}{0.0277}=\dfrac{0.11}{0.0277}=3.964$

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

$P-value=2\cdot P(t>3.964)=0.000078$

As the P-value (0.000078) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the accident proportions differ between the two age groups.

If we want to calculate the bounds of a 95% confidence interval, we start by calculating the margin of error.

For a 95% CI, the critical value for z is z=1.96.

Then, the margin of error is:

$MOE=z \cdot s_{p1-p2}=1.96\cdot 0.0277=0.0544$

Then, the lower and upper bounds of the confidence interval are:

$LL=(p_1-p_2)-z\cdot s_{p1-p2} = 0.11-0.0544=0.05561\\\\UL=(p_1-p_2)+z\cdot s_{p1-p2}= 0.11+0.0544=0.16439$

The 95% confidence interval for the population mean is (0.0556, 0.1644).

5 0

3 years ago

Find three positive integers ( a , b, and c ) such that a4 + b3 = c2

Lena [83]

A = 1
b = 2
c = 3
1 + 8 = 9

7 0

3 years ago