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2 years ago

Find the reciprocal of the following: a.) 2/18 b.)7/8 c.) 30/36

Mathematics

1 answer:

matrenka [14]2 years ago

7 0

Answer:

a) 9

b) 8/7

c) 36/30

Step-by-step explanation:

Reciprocal is when the denominator and numerator "flip."

comment if you have any more questions :)

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Hey what's the answer ? <img src="https://tex.z-dn.net/?f=%28x%20-%20y%29" id="TexFormula1" title="(x - y)" alt="(x - y)"

Varvara68 [4.7K]

Answer:

 -1

Step-by-step explanation:

here's your solution

=> The value of x = 1

=> The value of y = 2

=> we need to find ( x - y)

=> so, put the value of above variables in it

=> hence, (1 - 2) = - 1

=> - 1 is correct answer

hope it helps

3 0

3 years ago

Raymond uses the Venmo

Arisa [49]

Answer:

2.29

Step-by-step explanation:

2.95 plus 1.26 is 4.21, and 6.50 minus 4.21 is 2.29.

5 0

3 years ago

In a drama classroom, 75% of the students are chosen to perform a play. Of those choosen, 15% have singing roles. What is the pr

Nikolay [14]

Answer:

1/5 or 0.2

Step-by-step explanation:

probability=No of students with singing roles/No of people in the play
15/75=1/5 or 0.2

4 0

3 years ago

Kaliska is jumping rope. The vertical height of the center of her rope off the ground R(t) (in cm) as a function of time t (in s

xz_007 [3.2K]

Answer:

R (t) = 60 - 60 cos (6t)

Step-by-step explanation:

Given that:

R(t) = acos (bt) + d

at t= 0

R(0) = 0

0 = acos (0) + d

a + d = 0 ----- (1)

After $\dfrac{\pi}{12}$ seconds it reaches a height of 60 cm from the ground.

i.e

$R ( \dfrac{\pi}{12}) = 60$

$60 = acos (\dfrac{b \pi}{12}) +d --- (2)$

Recall from the question that:

At t = 0, R(0) = 0 which is the minimum

as such it is only when a is negative can acos (bt ) + d can get to minimum at t= 0

Similarly; 60 × 2 = maximum

R'(t) = -ab sin (bt) =0

bt = k π

here;

k is the integer

making t the subject of the formula, we have:

$t = \dfrac{k \pi}{b}$

replacing the derived equation of k into R(t) = acos (bt) + d

$R (\dfrac{k \pi}{b}) = d+a cos (k \pi)$ $= \left \{ {{a+d \ for \ k \ odd} \atop {-a+d \ for k \ even}} \right.$

Since we known a < 0 (negative)

then d-a will be maximum

d-a = 60 × 2

d-a = 120 ----- (3)

Relating to equation (1) and (3)

a = -60 and d = 60

∴ R(t) = 60 - 60 cos (bt)

Similarly;

For $R ( \dfrac{\pi}{12})$

$R ( \dfrac{\pi}{12}) = 60 -60 \ cos (\dfrac{\pi b}{12}) =60$

where ;

$cos (\dfrac{\pi b}{12}) =0$

Then b = 6

∴

R (t) = 60 - 60 cos (6t)

7 0

2 years ago

The function f is defined on the real numbers by f(x) = x + 2 What is the value of f(-3)?

kvasek [131]

Answer:

-1

Step-by-step explanation:

We can plug in -3 for x and solve:

f(-3) = -3 + 2

= -1

6 0

2 years ago