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jarptica [38.1K]
4 years ago
14

Write four decimals with the digit 4 in a different place in each ones, thenths,hundredths, and thousandths.Then write a stateme

nt that compares the value of the digit 4 in the different decimals.
Mathematics
1 answer:
dolphi86 [110]4 years ago
3 0

The number 87.65487.65487, point, 654 can be placed on a place value chart as follows:

Tens Ones . Tenths Hundredths Thousandths

888 777 ..point 666 555 444  

Decimal place value

The first digit after the decimal represents the tenths place. The next digit after the decimal represents the hundredths place. The remaining digits continue to fill in the place values until there are no digits left.

Example: 0.810.810, point, 81

The number 0.\blueD8\greenD10.810, point, start color blueD, 8, end color blueD, start color greenD, 1, end color greenD is made up of \blueD88start color blueD, 8, end color blueD tenths and \greenD11start color greenD, 1, end color greenD hundredth.

We can also write this as:

0.\blueD8\greenD1=\blueD{0.8}+\greenD{0.01}0.81=0.8+0.010, point, start color blueD, 8, end color blueD, start color greenD, 1, end color greenD, equals, start color blueD, 0, point, 8, end color blueD, plus, start color greenD, 0, point, 01, end color greenD

or

0.\blueD8\greenD1=\blueD{\dfrac8{10}}+\greenD{\dfrac1{100}}0.81=  

10

8

​  +  

100

1

​  0, point, start color blueD, 8, end color blueD, start color greenD, 1, end color greenD, equals, start color blueD, start fraction, 8, divided by, 10, end fraction, end color blueD, plus, start color greenD, start fraction, 1, divided by, 100, end fraction, end color greenD

Or we can use a place value chart:

Ones . Tenths Hundredths

000 ..point \blueD88start color blueD, 8, end color blueD \greenD11start color greenD, 1, end color greenD

Want to learn more about decimal place value? Check out this video.

Want to review whole number place value? Check out this article.

Practice

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Which linear equation represents a line with a slope of -7 and a y-intercept of 12
notka56 [123]

Answer:

<u>Answer</u><u> </u><u>→</u><u> </u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>7</u><u>x</u><u> </u><u>+</u><u> </u><u>1</u><u>2</u>

Step-by-step explanation:

General equation of a line:

\hookrightarrow \: { \tt{y = mx + c}} \\

  • m is the slope
  • c is the y intercept

From the question;

m is -7

c is 12

{ \tt{y =  - 7x + 12}}

4 0
3 years ago
Convert these unlike fractions to equivalent like fractions and add them. You must use the lcd to get the answer correct. If pos
ra1l [238]

Unlike fraction 1/7 is converted to equivalent  like fraction 2/14 and the sum of 2/14 + 3/14 = 5/14.

As given in the question,

Given fraction is equal to:

1/7=? + 3/14=?

Here there are two fractions

1/7 and 3/14

LCD( least common denominator) of 7 and 14 is equal to 14.

Now make them like fractions

1/7 is equivalent to

( 1/7) × ( 2/2) = 2/ 14

Now 2/14 and 3/14 are like fractions

Sum of like fractions is:

2/14 + 3/14

= ( 2+ 3) / 14

= 5/ 14

Therefore, the conversion of unlike fraction 1/7 to like fraction is 2/14. And sum of 2/14 + 3/14 = 5/14.

The complete question is:

Convert these unlike fractions to equivalent like fractions and add them. You must use the LCD to get the answer correct. If possible, reduce the final sum. 1/7=? + 3/14=?

Learn more about fractions here

brainly.com/question/10354322

#SPJ4

4 0
1 year ago
Indicate which property is illustrated in Step 1.
o-na [289]
In step 1 , it's commutative property of addition

hope it helps
4 0
3 years ago
jason has 150 cents nickels and quarters. if the number of nickels he has is 5 less than the twice the number of quarters, how m
eimsori [14]
Let's set up some simultaneous equations. Let the number of nickels be n, and the number of quarters be q. Now I'm from England so I had to look up the value of a nickel (I could guess the quarter though to be 25c), but apparently it's 5c

Okay we know that the total value of the coins is 150. This gives:

25q + 5n = 150

Rearranging to make n the subject:

n = 30 - 5q

Next, we use the second statement:

n = 2q - 5

Substituting this into the first equation:

2q - 5 = 30 - 5q
7q = 35
q = 5

Putting this value for q into the first equation:

n = 30 - 5(5) = 5

Hence he has 5 of each coin. I hope this helps :)
4 0
3 years ago
A recipe for chocolate chip cookies mixes 512 cups of cookie dough with 34 cup of chocolate chips and makes 48 cookies. A baker
kvasek [131]

Answer:

2

Step-by-step explanation:

3 0
3 years ago
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