Find the number of permutations in the word “embarrass”.

In a word processing document or on a separate piece of paper, use the guide to construct a two column proof proving that lines

lorasvet [3.4K]

Hello

just a second

people reading this please complete because you will help me a lot.

I am an Indian girl my name is Lamer and am 13 years old.

I Just got this new device after working at a farm for 2 years.

I used to use brainly at my friend device she had money to buy brainly plus.

I cant please help me get points so I can get good marks and my dad let me complete my education instead of getting married.

8 0

3 years ago

HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP

insens350 [35]

ITS B. The range is the stuff in the right circle. So its 245

6 0

3 years ago

An automobile manufacturer has given its van a 59.5 miles/gallon (MPG) rating. An independent testing firm has been contracted t

LekaFEV [45]

Answer:

The pvalue of the test is 0.0124 < 0.1, which means that there is sufficient evidence at the 0.1 level to support the testing firm's claim.

Step-by-step explanation:

An automobile manufacturer has given its van a 59.5 miles/gallon (MPG) rating. An independent testing firm has been contracted to test the actual MPG for this van since it is believed that the van has an incorrect manufacturer's MPG rating:

At the null hypothesis, we test if the mean is the same, that is:

$H_0: \mu = 59.5$

At the alternate hypothesis, we test that it is different, that is:

$H_a: \mu \neq 59.5$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

59.5 is tested at the null hypothesis:

This means that $\mu = 59.5$

After testing 250 vans, they found a mean MPG of 59.2. Assume the population standard deviation is known to be 1.9.

This means that $n = 250, X = 59.2, \sigma = 1.9$

Value of the test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{59.2 - 59.5}{\frac{1.9}{\sqrt{250}}}$

$z = -2.5$

Pvalue of the test and decision:

The pvalue of the test is the probability of finding a mean that differs from 59.5 by at least 0.3, which is P(|Z|>-2.5), which is 2 multiplied by the pvalue of Z = -2.5.

Looking at the z-table, Z = -2.5 has a pvalue of 0.0062

2*0.0062 = 0.0124

The pvalue of the test is 0.0124 < 0.1, which means that there is sufficient evidence at the 0.1 level to support the testing firm's claim.

5 0

3 years ago

Please help me with this question

Andreyy89

Answer:

the slope is -3, the slope is negative, the y-intercept is 0

Step-by-step explanation:

this ones are the ones that apply to the graph

4 0

3 years ago

Read 2 more answers

Sofia can type the work in 10 hours. Nova can do it in 15 hours. They work together for 4 hours, then Sofia and Nova finish the

AlladinOne [14]

Answer:

2 days.

Step-by-step explanation:

Let, Sofia can type the x amount of work in 10 hours.

So, in one hour Sofia can type $\frac{x}{10}$ amount of work.

Again, Nova can type x amount of work in 15 hours.

So, in one hour Nova can type $\frac{x}{15}$ amount of work.

Hence, if they work together, they can type $\frac{x}{10} + \frac{x}{15} = \frac{6x + 4x}{60} = \frac{10x}{60} = \frac{x}{6}$ amount of work in one hour.

Therefore, working together they can type the x amount of work in $\frac{x}{\frac{x}{6} } = 6$ days.

So, they have to work for (6 - 4) = 2 days more to finish the work. (Answer)

6 0

4 years ago

Read 2 more answers