Ask question

Ask question

All categories

igor_vitrenko [27]

3 years ago

5

Find the number of permutations in the word “embarrass”.

1 answer:

raketka [301]3 years ago

7 0

4 I think i'm sorry if I get it wrong. Hope I helped ≥ω≤

You might be interested in

Deffense [45]

Answer:

ohhhhhh grlll u aare so good when it comes to writing i should be a song writer

6 0

3 years ago

Read 2 more answers

89.517 +59.84 by first rounding each number to the nearest whole number.

Nataliya [291]

Answer:

150

Step-by-step explanation:

89.517=90. 59.84=60 90+60=150

4 0

3 years ago

Read 2 more answers

A teacher has two students, one two times as old as the other. The teacher is five times as old as the older student, and in 5 y

Daniel [21]

Let x = the older student
Let y = the younger student
Let z = the teacher.

x = 2y
z = 5x
z + 5 = 5y Somehow this does not look like its going to be nice.
z = 5y - 5
Since z = 5y - 5 we have
5y - 5 = 5x
y - 1 = x Here's the problem. there is a contradiction. You need to make y bigger, not smaller.

6 0

3 years ago

HELP NOW!! PLEASE!! I NEED HELP!!!!

timama [110]

Answer:

-2

Step-by-step explanation:

14/7 = 2

So,

-14/7 = -2

Check:

-2 x 7 = -14

7 0

3 years ago

Read 2 more answers

Determine whether the three points are collinear. (3, -10), (-2, -7), (0, -5)

Mumz [18]

The points are not collinear.

Solution:

Let A, B and C be (3, -10), (-2, -7) and (0, -5).

<em>If slopes of any two points are same, then the points are collinear.</em>

Slope formula:

$$m=\frac{y_2-y1}{x_2-x_1}$

<u>Slope of AB:</u>

$$m_1=\frac{-7-(-10)}{-2-3}$

$$m_1=\frac{-7+10}{-5}$

$$m_1=-\frac{3}{5}$

<u>Slope of BC:</u>

$$m_2=\frac{-5-(-7)}{0-(-2)}$

$$m_2=\frac{-5+7}{2}$

$$m_2=\frac{2}{2}$

$m_2=1$

<u>Slope of CA:</u>

$$m_3=\frac{-10-(-5)}{3-0}$

$$m_3=\frac{-10+5}{3}$

$$m_3=-\frac{5}{3}$

$m_1\neq m_2 \neq m_3$

Slope of AB ≠ Slope of BC ≠ Slope of AC

Therefore the points are not collinear.

6 0

3 years ago