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3 years ago

How many moles of caco3 are there in an antacid tablet containing 0.515 g caco3?

2 answers:

8 0

The moles of CaCO3 which are there in antacid tablet that contain 0.515g CaCO3 is calculated as follows

moles =mass/molar mass

the molar mass of CaCO3 = ( 40 x1)+ (12 x 1) + (16 x 3)= 100 g/mol

moles is therefore= 0.515g/100 g/mol= 5.15 x10^-3 moles

Sunny_sXe [5.5K]3 years ago

3 0

Answer:

$0.00515molCaCO3$

Explanation:

Hello,

By following the down below simple mass-mole relationship, the requested moles are computed, considering that the calcium carbonate has a molecular mass of 100g/mol:

$M_{CaCO3}=40+12+16*3=100g/mol\\\\n_{CaCO3}=0.515gCaCO3*\frac{1molCaCO3}{100gCaCO3}=0.00515molCaCO3$

Best regards.

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As a chemist for an agricultural products company, you have just developed a new herbicide,"Herbigon," that you think has the po

Ganezh [65]

Answer:

pH = 2.03

Explanation:

The pH can be calculated using the following equation:

$pH = -log [H_{3}O^{+}]$ (1)

The concentration of H₃O⁺ is calculated using the dissociation constant of the next reaction:

CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺

1.00 M

$K_{a} = \frac{[CH_{3}COO^{-}][H_{3}O^{+}]}{[CH_{3}COOH]}$

Solving the above equation for H₃O⁺, we have:

$[H_{3}O^{+}] = \frac{Ka*[CH_{3}COOH]}{[CH_{3}COO^{-}]}$ (2)

The dissociation constant is equal to:

$pKa = -log(Ka) \rightarrow Ka = 10^{-pKa} = 10^{-4.76} = 1.74 \cdot 10^{-5}$

Now, by solving the equation of the solubility product for Herbigon, we can find [CH₃COO⁻]:

CH₃COOX ⇄ CH₃COO⁻ + X⁺

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$K_{sp} = [CH_{3}COO^{-}][X^{+}]$

$[CH_{3}COO^{-}] = \frac{K_{sp}}{[X^{+}]} = \frac{9.40 \cdot 10^{-6}}{5.00 \cdot 10^{-3}} = 1.88 \cdot 10^{-3} M$

By entering the values of [CH₃COO⁻] and Ka, into equation (2) we can calculate [H₃O⁺]:

$[H_{3}O^{+}] = \frac{1.74 \cdot 10^{-5}*[1.00]}{[1.88 \cdot 10^{-3}]} = 9.26 \cdot 10^{-3} M$

Hence, the pH is:

$pH = -log [H_{3}O^{+}] = -log [9.26 \cdot 10^{-3}] = 2.03$

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4 years ago

One mole of silver has a mass of 107.9 grams. Approximately how many atoms of silver are present in one mole of silver?

irga5000 [103]

Answer:

The number of atoms in 1 mole silver is also 6.022 *10^23 atoms.

Option C is correct.

Explanation:

Step 1: Data given

Mass of 1 mole silver = 107.9 grams

Step 2: Calculate the number of atoms in 1 mole of silver

To calculate the number of atoms in 1 mole, we multiply the number of Avogadro by the number of moles

Number of atoms = 1 mol * 6.022 *10^23 atoms/ mol

Number of atoms = 6.022 * 10^23 atoms

Since the number of Avogadro says there are 6.022 * 10^23 atoms per 1 mole. The number of atoms in 1 mole silver is also 6.022 *10^23 atoms.

Option C is correct.

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4 years ago

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Oxana [17]

Answer:

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