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butalik [34]
3 years ago
5

Why do farmers spray water over their crops before a frost?

Chemistry
1 answer:
Nezavi [6.7K]3 years ago
5 0

Answer:

When water freezes and turns into ice, it releases latent heat. Then, the ice that builds up on the plant will insulate it from the colder surrounding air temperatures. Because of this, some growers choose to spray their crop with water before the freeze occurs.

Explanation:

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Someone plz give me a hand​
Anika [276]

Answer:

If I am not mistaking and correct me if I am wrong on this but I think the answer is C

Explanation:

If this is correct please let me know and maybe a brainliest <3

8 0
3 years ago
¿Aproximadamente cuántos gramos de KNO3
Tanya [424]

Answer:

65

Explanation:

100-35=65 es demasiado facil

3 0
3 years ago
Read 2 more answers
Clasifica según sea: solución, coloide o suspensión.
makkiz [27]

Answer:

Sal, cobre, aluminio, anillo de oro puro Oxígeno ------ suspensión.

Cerveza, carbonato de sodio, oxígeno, carbono y helio ------ solución.

Explicación:

Sal, Cobre, Aluminio, Anillo de oro puro Oxígeno son los ejemplos de suspensión porque permanecen suspendidos en la solución mientras que por otro lado, Cerveza, Carbonato de sodio, Oxígeno, Carbono y helio son los ejemplos de solución porque formaron una mezcla homogénea en la que ambas soluciones no se pueden diferenciar entre sí pero en suspensión sí se pueden diferenciar.

4 0
3 years ago
Sedimentary rocks are described as small pieces of rock and animal remains that are weathered, swept downstream and then settle,
ss7ja [257]

True,  when small pieces of rock and animal remains weather over the years it sometimes get carried down stream then form a layer of rock. over years different types of rocks settle in the same place and compacts the rocks beneath it forming another layer.

5 0
3 years ago
Iodine is prepared both in the laboratory and commercially by adding Cl2(g) to an aqueous solution containing sodium iodide. 2Na
otez555 [7]

Answer:

79.0 g

Explanation:

1. Gather the information in one place.

MM:    148.89        253.81

           2NaI + Cl2 → I2 + 2NaCl

m/g:                         67.3

2. Moles of I2

n = 67.3 g × (1 mol/253.81 g) = 0.2652 mol I2

2. Moles of NaI needed

From the balanced equation, the molar ratio is 2 mol NaI: 1 mol I2

n = 0.028 76 mol I2× (2 mol NaI/1 mol I2) = 0.5303 mol NaI

3. Mass of NaI

m = 0.5303 mol × (148.89 g/1 mol) = 79.0 g NaI

It takes 79.0 g of NaI to produce 67.3 g of I2.

6 0
4 years ago
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