<span> Au</span>₂(SeO₄)₃
O = -2 × 4 = -8
Se = + 6
So,
(+6 - 8) = -2
Means (SeO₄) contains -2 charge, Now multiply -2 by 3
-2 ₓ 3 = -6
Means,
Au₂ + (-6) = 0
Au₂ = +6
Or,
Au = 6 / 2
Au = +3
Result:
Au = +3
Se = +6
O = -2
Ni(CN)₂
Cyanide (CN⁻) contains -1 charge,
So,
N = -3
C = +2
Then,
Ni + (-1)₂ = 0
Ni - 2 = 0
Or,
Ni = +2
Result:
N = -3
C = +2
Ni = +2
Answer:
hinndndnnddnndndndnd do djfj
Explanation:
hdhdjdbdndndndjjddjdndjdjdndnndndndnd be rnnrbr
Answer:
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Hope this helps :)
Answer:
The volume of a 76.52 g sample of methane gas is
32.7 L at 26.9 °C and 4.45 atm. What will its volume be at 95.4 °C and 1.7 atm?
<span>Mendeleev left gaps in his periodic table because the properties of known elements predicted other, as-yet-undiscovered, elements in these locations. As Mendeleev organized his periodic table, he recognized that these gaps would be filled as future scientists identified new elements.</span>
