Answer:
Explanation:
The correct answer is 19, 20 DHDP is more polar than DHA. This is as a result of the presence of two hydroxyl groups.
Answer:
Q:
What volume will 3.50 mol of Xe gas occupy at STP?
A:
78.4 L
Explanation:
Answer:
k = 4.85 x 10⁻³ / s
Explanation:
For a first order reaction we have two very important equations we need to memorize:
ln ( N/N₀ ) = -kt
and,
0.693/ k = t₁/₂
where k is the rate constant and t i is the halflife which can be derived from the first equation.
0.693/ k = t₁/₂ ⇒ k = 0.693 / t₁/₂
k = 0.693 / 143 s = 4.85 x 10⁻³ / s
Answer:
(C) It is favorable and is driven by ΔH° only.
Explanation:
Let's consider the following balanced equation.
2 Na₂O₂ + S + 2 H₂O → 4 NaOH + SO₂
To determine whether it will be favorable or not at 298 K, we need to calculate the standard Gibbs free energy (ΔG°).
- If ΔG° < 0, the reaction will be favorable.
- If ΔG° > 0, the reaction will be unfavorable.
We can calculate ΔG° using the following expression.
ΔG° = ΔH° - T.ΔS°
As we can see from the expression above, the favorability will be driven if ΔH° < 0 and if ΔS° < 0. Since ΔH° = -610 kJ/mol and ΔS° = -73 J/K.mol, the favorability will be driven by ΔH°. Now, let's calculate the overall favorability.
ΔG° = ΔH° - T.ΔS°
ΔG° = -610 kJ/mol - 298 K.(-0.073 kJ/K.mol) = -588 kJ/mol
The reaction is favorable and is driven by ΔH° only.
