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Kaylis [27]
3 years ago
11

What is public property​

Chemistry
2 answers:
Ne4ueva [31]3 years ago
7 0

Answer:

ur mom

Explanation:

Naily [24]3 years ago
6 0

Answer:

the property that is dedicated to public use

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What pressure is required to reduce 40 ml of a gas at standard conditions to 20 ml at a temperature of 21?c? answer in units of
ElenaW [278]
If you need half the volume, you need double the pressure (V * p). Normal air pressure in the atmosphere is 101300 Pa so that means you need double that, thus 202600 Pa (or 2,026 bars)

4 0
3 years ago
Please helpppppppppppppppp!!!!!!!!!!!!!!!
Agata [3.3K]

Answer:

c MgO

Explanation:

product is located after the reaction arrow

8 0
3 years ago
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How can you make a solution saturated
Vlada [557]
You add solute until it can't dissolve anymore.
3 0
4 years ago
I need help with this plz help
schepotkina [342]

Answer:

\rm ^{103}_{\phantom{1}40}Zr, zirconium-103.

Explanation:

In a nuclear reaction, both the mass number and atomic number will conserve.

Let ^{A}_{Z}\mathrm{X} represent the unknown particle.

The mass number of a particle is the number on the upper-left corner. The atomic number of a particle is the number on its lower-left corner under the mass number. For example, for the particle ^{A}_{Z}\mathrm{X}, A is the mass number while Z while Z is the atomic number.

Sum of mass numbers on the left-hand side of the equation:

\underbrace{239}_{^{239}_{\phantom{2}94}\mathrm{Pu}} + \underbrace{1}_{^{1}_{0}\mathrm{n}} = 240.

Note that there are three neutrons on the right-hand side of the equation. Sum of mass numbers on the right-hand side:

\underbrace{A}_{^{A}_{Z}\mathrm{X}} + \underbrace{134}_{^{134}_{\phantom{2}54}\mathrm{Xe}} + \underbrace{3\times 1}_{3\;^{1}_{0}\mathrm{n}} = A + 137.

Mass number conserves. As a result,

A + 137 = 240.

Solve this equation for A:

A = 103.

Among the five choices, the only particle with a mass number of 103 is \rm ^{103}_{\phantom{1}40}Zr. Make sure that atomic number also conserves.

3 0
3 years ago
What mass of AgCl is produced when 53.42 g of AgNO3 reacts with 14.19 g of NaCl?
Leya [2.2K]

Answer is: mass of silver chloride is 34,82 g.

Chemical reaction: AgNO₃ + NaCl → AgCl + NaNO₃.

<span>m(AgNO</span>₃) = 53,42 g..<span>
m(NaCl) = 14,19 g.
n(AgNO</span>₃) = m(AgNO₃) ÷ M(AgNO₃).<span>
n(AgNO</span>₃) = 53,42 g ÷ 169,87 g/mol.

n(AgNO₃) = 0,314 mol.

n(NaCl) = 14,19 g ÷ 58,4 g/mol.

n(NaCl) = 0,242 mol; limiting reactant.

From chemical reaction: n(NaCl) : n(AgCl) = 1 : 1.<span>
n</span>(AgCl)<span> = 0,242 mol.
m</span>(AgCl) = 0,252 mol · 143,32 g/mol.

m(AgCl) = 34,82 g.

7 0
3 years ago
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