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topjm [15]
3 years ago
6

A candy bar cost the store $0.79. The store wants a 65% mark up. What would the price of the candy bar be to have a 65% mark up?

Mathematics
1 answer:
kozerog [31]3 years ago
5 0

Answer:

1.30$

Step-by-step explanation:

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The mean weight of the domesticated house cat is 9.2 pounds with a standard deviation of 3.4 pounds. If a cat has a z-score of -
ra1l [238]

Answer:

4.78 pounds

Step-by-step explanation:

We solve the above question using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = 9.2 pound

σ is the population standard deviation = 3.4 pounds

z = 1.3

We are to find x

Hence,

-1.3 = x - 9.2/3.4

Cross Multiply

-1.3 × 3.4 = x - 9.2

-4.42 = x - 9.2

x = -4.42 + 9.2

x = 4.78 pounds.

Therefore the weight of the cat is 4.78 pounds

5 0
3 years ago
What does x equal in this equation<br><br>1/4(x-16)=3/4(x+20)?<br>​
erma4kov [3.2K]

Answer:

1/4x - 4 = 3/4x - 15

-1/2x - 4 = -15

-1/2x = -11

x = 22

6 0
3 years ago
How do you solve for "r" in the literal equation "I=Prt"
Mrac [35]
R=I/Pt
hopefully this helps
8 0
3 years ago
a broker gets rs 20000 as commission from sale of a piece of land which costs rs 8000000. Find the rate of commission.​
Airida [17]

Answer:

0.25%

Step-by-step explanation:

Rate of commission

= (commission*100)/cost of land

=( 20000*100)/8000000

= 2000000/8000000

=2/8

= 0.25%

3 0
3 years ago
A jet travels from chicago to kansas city at a speed of 440 knots. If it takes a plane 3 hr longer to fly from kansas city to ch
steposvetlana [31]

d = distance between the two cities

v₁ = average speed while going from chicago to kansas city = 440 knots

t₁ = time taken to travel distance going from chicago to kansas city

time taken to travel distance going from chicago to kansas city is given as

t₁ = d/v₁

t₁ = d/440                                        eq-1


v₂ = average speed while going from kansas city to chicago = 110 knots

t₂ = time taken to travel distance going from kansas city to chicago

time taken to travel distance going from kansas city to chicago is given as

t₂ = d/v₂

t₂ = d/110                                                     eq-2


Given that :

t₂ = t₁ + 3

using eq-1  and eq-2

(d/110) = (d/440) + 3

d = 440

7 0
3 years ago
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