Question

Find the mean of the data summarized in the given frequency distribution. Compare the computed mean to the actual mean of 50.7 degrees. Low Temperature ​(circle​F) 40minus44 45minus49 50minus54 55minus59 60minus64 Frequency 2 7 9 5 1 The mean of the frequency distribution is nothing degrees. ​(Round to the nearest tenth as​ needed.)

Answer 1

Answer: The mean of the frequency distribution is 51.7°.

The computed mean 51.7° is greater than the actual mean 50.7° .

Step-by-step explanation:

The given table :

  Low Temperature ​(°​F)      Frequency     Mid -value  

      Class interval                  f                        x                  fx

          40-44                           2                     42.5               85

          45-49                           7                     47.5               95                      

          50-54                          9                     52.5               105

           55-59                         5                     57.5                115

           60-64                          1                      62.5               25

$\text{Now, Mean}=\dfrac{\sum fx}{\sum f}\\\\=\dfrac{85+332.5+472.5+287.5+62.5}{24}\\\\=\dfrac{1240}{24}=51.6666666667\approx51.7$

The computed mean 51.7° is greater than the actual mean 50.7° .