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madreJ [45]
3 years ago
5

What is the equation for 5 more than 3 times a number is 0

Mathematics
1 answer:
Sedaia [141]3 years ago
5 0

Answer: 9

Step-by-step explanation:

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Cheryl wants to have $2300 in spending money to take on a trip to Disney World in three years. How much must she deposit now in
Savatey [412]

Use the compound amount formula:

$2,300 = P(1+0.02)^3.  Solve this for P:

P = $2,300 / (1.02)^3 =  $2167.34.

By depositing $2,167.34 now, Cheryl would have $$2300 after three years.


4 0
3 years ago
Can someone please help me please I really need help please answer it correctly
kvv77 [185]

Answer:

<h3>Princeton Florist</h3>

Let the total charge is y, the number of small arrangements is x.

<u>Total charge will be:</u>

  • y = 13x + 47
<h3>Chad's Flowers</h3>

<u>Total charge will be:</u>

  • y = 17x + 35

<u>Since the total charge is same in both shops, we have:</u>

  • 13x + 47 = 17x + 35

<u>Solve for x:</u>

  • 17x - 13x = 47 - 35
  • 4x = 12
  • x = 3

<u>Total cost is:</u>

  • 13*3 + 47 = 39 + 47 = 86

<u>Small arrangements</u> = 3, <u>cost </u>= $86

7 0
2 years ago
Felicia installed a new pool for $17,190 using a 12-month deferred payment plan with an interest rate of 18.67%. What is the bal
fgiga [73]

Answer: c. $13.620.76

Step-by-step explanation:

4 0
3 years ago
Please help giving brainliest
jekas [21]
28.26 cause it is trust me
6 0
2 years ago
Read 2 more answers
Find the solution(s) to 2x2 + 5x – 3 = 0.
iren2701 [21]

Answer:

C and E

Step-by-step explanation:

Let's factor this the "old fashioned" way.  The standard form of a quadratic is

y=ax^2+bx+c

If you're familiar with the quadratic formula I'd say throw it into that, but if not, again, let's do it the "old fashioned" way.  

We need to find the product of our a and c.  Our a = 2 and our c = -3.  So that gives us a -6.  Now we have to find the factors of 6 (the negative right now doesn't matter so much).  The factors of 6 are 1, 6  and 2, 3.  Both of those possibilities will work to give us a +5, which is the linear term.  Puttng in the 2, 3 first:

0=2x^2+3x+2x-3

Now group the terms together into groups of 2:

0=(2x^2+3x)+(2x-3)

The idea is to factor out something common in each term so that what's left over in the parenthesis in both terms is exactly the same.  In the first term we can factor out a common x, and in the second term, the only thing common is a 1.  So that looks like this:

x(2x+3)+1(2x-3)

What's inside those parenthesis are not actually identical, so 2 and 3 won't work.  Lets try 1 and 6.  For those 2 numbers to equal a +5, the 6 is positive and the 1 is negative.  So let's try that:

(2x^2+6x)+(-x-3)

In the first term we can factor out the common 2x and in the second term we can factor out the common -1:

2x(x + 3) - 1(x + 3)

Now what's common is (x + 3), so we can factor THAT out and what is left over is 2x - 1:

(x + 3)(2x - 1) = 0

If x + 3 = 0, then x = -3

and if 2x - 1 = 0, then 2x = 1 and x = 1/2

5 0
2 years ago
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