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iragen [17]
4 years ago
7

Answer number one asap this is not a joke so please not random cmts thx will report if u do!

Mathematics
1 answer:
STALIN [3.7K]4 years ago
8 0
1. The area of one face of the bar is
.. face area = (50 mm)*(90 mm) = 4500 mm^2
The area of two sides of the bar is
.. side area = (50 mm +90 mm)*(3.5 mm) = 490 mm^2

Together, those areas cover half the bar, so the total paper required is
.. 2*(4500 mm^2 +490 mm^2) = 9980 mm^2 . . . . . . 3rd selection

2. The length of the central rectangle is
.. 8 ft + 6 ft + 10 ft = 24 ft
Its width is 7 ft, so its area is
.. Arect = (7 ft)*(24 ft) = 168 ft^2

Each of the two triangles has a base of 8 ft and a height of 6 ft, so together, they have an area of
.. Atriangles = (8 ft)*(6 ft) = 48 ft^2

Then the total area of the prism is
.. Atotal = Arect +Atriangles
.. = (168 ft^2) +(48 ft^2)
.. = 216 ft^2
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The points obtained by students of a class in a test are normally distributed with a mean of 60 points and a standard deviation
Paraphin [41]

Answer:

0.13% of students have scored less than 45 points

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 60, \sigma = 5

About what percent of students have scored less than 45 points?

This is the pvalue of Z when X = 45. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{45 - 60}{5}

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Z = -3 has a pvalue of 0.0013

0.13% of students have scored less than 45 points

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