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2 years ago

15

You pay $6 in tax on a $30 purchase. What is the tax percent.

1 answer:

marin [14]2 years ago

4 0

Answer:

20%

Step-by-step explanation:

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A rocket is launched from a height of 3m with an initial velocity of 15 m/s at what time will the rocket be 13m from the ground?

dem82 [27]

Not sure of my answer but, velocity=delta d/delta t. t=delta d/ velocity
—> t=(13-3)/15=>10/15=2/3s

4 0

1 year ago

In ABC the measure of angle A is 2x+4 , the measure of angle B is 4x+2 , and the measure of angle C is 2x-1. What are the measur

Lynna [10]

(2x+4)+(4x+2)+(2x-1)=180
8x+5=180°
8x=180-5
8x=175
X=21.875
A= 2(21.875)+4=47.75
B=4(21.875)+2 =89.5
C=2(21.875)-1=42.75

5 0

2 years ago

Read 2 more answers

If the third term in a geometric sequence is 20, and the fifth term in the sequence is 5, what is the ratio (multiplier)?

Talja [164]

Term:    3    4      5
Value 20    ..      5
          20 20r 20r^2
So 20r^2 = 5
         r^2 = 1/4
           r = 1/2

5 0

2 years ago

Given a right triangle with a hypotenuse of 6 cm and a leg of 4cm, what is the measure of the other leg of the triangle rounded

slega [8]

Answer:

$4.5 cm=L2$

Step-by-step explanation:

This problem can be solved using the pythagorian theoreme:

$H=\sqrt{L1^{2}+L2^{2} }$

Where:

$H=6 cm$

$L1=4 cm$

$L2=?$

We isolate our incognita an we get:

$\sqrt{H^{2}-L1^{2}} =L2$

We supplant with the given data:

$\sqrt{(6cm)^{2}-(4cm)^{2}} =L2$

$\sqrt{36cm^{2}-16cm^{2}} =L2$

$\sqrt{36cm^{2}-16cm^{2}} =L2$

$\sqrt{20cm^{2}} =L2$

$4.5 cm=L2$

5 0

2 years ago

Zubin has two pieces of string. One piece is 36 inches long and the other is 48 inches long. He wants to cut them into equal pie

skelet666 [1.2K]

Answer:

12 pieces each:

$S_1 = 3\ in$

$S_2= 4\ in$

Step-by-step explanation:

Given

$S_1 = 36\ in$ -- first string

$S_2 = 48\ in$ --- second string

Required

Determine the number of equal pieces

To do this, we first calculate the HCF of the length of both pieces $(36\ and\ 48)$

$36 = 2 * 2 * 3 * 3$

$48 = 2 * 2 * 2 * 2 * 3$

$Common\ prime\ factors = 2, 2\ and\ 3$

The HCF is:

$HCF = 2 * 2 * 3$

$HCF = 12$

<em>Hence, he can cut both strings to 12 pieces each</em>

<em></em>

<em>Recall that </em>

$S_1 = 36\ in$

<em>The first string can then be cut in to 3 inches each (i.e. 36/12)</em>

$S_2 = 48\ in$

<em>The first string can then be cut in to 4 inches each (i.e. 48/12)</em>

7 0

2 years ago