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Rus_ich [418]
3 years ago
15

How many ways are there to distribute n distinct balls into r boxes (a box can contain any number of balls, ranging from zero (n

one) all the way to all n balls)?
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
5 0
<span>How many ways are there to distribute n distinct balls into r boxes (a box can contain any number of balls, ranging from zero (none) all the way to all n balls.</span>
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Vlad1618 [11]

Answer:

the answer is C

Step-by-step explanation:

{n}^{3}  = 380

\sqrt[3]{ {n}^{3} }  =  \sqrt[3]{380}

n = 7.25

7 < 7.25 <8

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2 years ago
What is the slope and the y intercept of the equation -5x+3y=15
Rina8888 [55]
Answer: the slope is 5/3 and the y-intercept is (0,5)
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3 years ago
HELP!! VERY TIME TIME SENSITIVE
guapka [62]

Answer:

B is your correct answer

Step-by-step explanation:

3 0
2 years ago
an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor
Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

--------------------------------

We suppose that tree diameters are normally distributed with <u>mean 8.8 inches and standard deviation 2.8 inches.</u>

<u />

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • The Z-score measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.<u> </u>

<u />

In this problem:

  • Mean of 8.8 inches, thus \mu = 8.8.
  • Standard deviation of 2.8 inches, thus \sigma = 2.8.

<u />

The interquartile range(IQR) is the difference between the 75th and the 25th percentile.

<u />

25th percentile:

  • X when Z has a p-value of 0.25, so X when Z = -0.675.

Z = \frac{X - \mu}{\sigma}

-0.675 = \frac{X - 8.8}{2.8}

X - 8.8 = -0.675(2.8)

X = 6.91

75th percentile:

  • X when Z has a p-value of 0.75, so X when Z = 0.675.

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 8.8}{2.8}

X - 8.8 = 0.675(2.8)

X = 10.69

The IQR is:

IQR = 10.69 - 6.91 = 3.78

What is the diameter, in inches, of the smallest tree that is an outlier?

  • The diameter is <u>1.5IQR above the 75th percentile</u>, thus:

10.69 + 1.5(3.78) = 16.36

The diameter of the smallest tree that is an outlier is of 16.36 inches.

<u />

A similar problem is given at brainly.com/question/15683591

3 0
2 years ago
15% of 25 is what? Please answer asap
olganol [36]

Answer: 3.75

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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