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3 years ago

If felicity plays 805 games and started in 569 of them in what fraction of the games did he start

Mathematics

1 answer:

slega [8]3 years ago

3 0

Answer:

0.706

Step-by-step explanation:

Felicity started in games = 569

Total number of games = 805

=> Fraction = 569/805

=> Fraction = 0.706

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The sum of two numbers is 300 and the two numbers have a ratio of 20:10. Find the larger number.

Komok [63]

Step-by-step explanation:

Let the two numbers be 20x and 10x

Then by the question,

20x + 10x = 300

or, 30x = 300

or, x = 300/ 30

x = 10

Now the larger number

20x = 20* 10 = 200.

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2 years ago

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3 years ago

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In a state lottery, 28 balls are numbered 1-28. Eight of them are randomly selected without replacement. To win, you only need t

podryga [215]

Answer:

2/7

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2 years ago

Please help ASAP! Thanks! For the figures below, assume they are made of semicircles, quarter circles and squares. For each shap

bazaltina [42]

Answer:

Part 1) $A=36(\pi-2)\ cm^2$

Part 2) $P=6(\pi+2\sqrt{2})\ cm$

Step-by-step explanation:

Part 1) Find the area

we know that

The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle

$A=\frac{1}{4}\pi r^{2}-\frac{1}{2}(b)(h)$

we have that the base and the height of triangle is equal to the radius of the circle

$r=12\ cm\\b=12\ cm\\h=12\ cm$

substitute

$A=\frac{1}{4}\pi (12)^{2}-\frac{1}{2}(12)(12)$

$A=(36\pi-72)\ cm^2$

simplify

Factor 36

$A=36(\pi-2)\ cm^2$

Part 2) Find the perimeter

The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle

<em>The circumference of a quarter of circle is equal to</em>

$C=\frac{1}{4}(2\pi r)=\frac{1}{2}\pi r$

substitute the given values

$C=\frac{1}{2}\pi (12)$

$C=6\pi\ cm$

The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)

$AC=\sqrt{12^2+12^2}$

$AC=\sqrt{288}\ cm$

simplify

$AC=12\sqrt{2}\ cm$

Find the perimeter

$P=(6\pi+12\sqrt{2})\ cm$

simplify

Factor 6

$P=6(\pi+2\sqrt{2})\ cm$

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2 years ago