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AleksandrR [38]

3 years ago

11

Ana drew a map of the Panama Canal in the scale Ana used for the map 4 centimeters represents 20 kilometers what is the scale fa

ctor
A. 4/20

B. 4

C. 1/5

D. 5

1 answer:

Ganezh [65]3 years ago

5 0

Answer:

D

Step-by-step explanation:

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Help me plz!!!!! I have no ideia how to do this

BlackZzzverrR [31]

Answer:

<h2>x² = -3</h2>

Step-by-step explanation:

In algebra, the goal is always to isolate the variable, so its value can be determined.

<h3>Step 1: Subtract 21</h3>

7x² = -21

<h3>Step 2: Divide by 7</h3>

x² = -3

<h3>Step 3: Check</h3>

7(-3) + 21 = 0

0 = 0 ✔

<h3>Step 4: Answer</h3>

x² = -3

I'm always happy to help :)

4 0

3 years ago

Wordly wise book 5 lesson 17

Novay_Z [31]

Answer: whats the question

Step-by-step explanation: put a image on the question

8 0

3 years ago

which expression is equivalent to 100 n2 − 1? (10n)2 − (1)2 (10n2)2 − (1)2 (50n)2 − (1)2 (50n2)2 − (1)2

givi [52]

Which expression is equivalent to 100 n2 − 1? (10n)2 − (1)2 (10n2)2 − (1)2 (50n)2 − (1)2 (50n2)2 − (1)2

Regroup:
100n^2-1

=10^2n^2-1
=(10n)^2-1^2

So the correct answer is :
(10n)^2-1^2

To attempt to factor a polynomial of four or more terms with no common factor, first rewrite it in groups. Each group may possibly be separately factored, and the resulting expression may possibly lend itself to further factorization if a greatest common factor<span> or special form is created.</span>

5 0

2 years ago

Read 2 more answers

Matt has a block he uses one of the flat surfaces of the block to trace triangle what type of solid figure Matt block

timama [110]

I think it's a rectangle block because the surface is flat on all the sides.

8 0

2 years ago

Suppose you just received a shipment of nine televisions. Three of the televisions are defective. If two televisions are randoml

Temka [501]

<h2>Answer:</h2>

a)

The probability that both televisions work is: 0.42

b)

The probability at least one of the two televisions does not work is:

0.5833

<h2>Step-by-step explanation:</h2>

There are a total of 9 televisions.

It is given that:

Three of the televisions are defective.

This means that the number of televisions which are non-defective are:

9-3=6

a)

The probability that both televisions work is calculated by:

$=\dfrac{6_C_2}{9_C_2}$

( Since 6 televisions are in working conditions and out of these 6 2 are to be selected.

and the total outcome is the selection of 2 televisions from a total of 9 televisions)

Hence, we get:

$=\dfrac{\dfrac{6!}{2!\times (6-2)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{\dfrac{6!}{2!\times 4!}}{\dfrac{9!}{2!\times 7!}}\\\\\\=\dfrac{5}{12}\\\\\\=0.42$

b)

The probability at least one of the two televisions does not work:

Is equal to the probability that one does not work+probability both do not work.

Probability one does not work is calculated by:

$=\dfrac{3_C_1\times 6_C_1}{9_C_2}\\\\\\=\dfrac{\dfrac{3!}{1!\times (3-1)!}\times \dfrac{6!}{1!\times (6-1)!}}{\dfrac{9!}{2!\times (9-2)!}}\\\\\\=\dfrac{3\times 6}{36}\\\\\\=\dfrac{1}{2}\\\\\\=0.5$

and the probability both do not work is:

$=\dfrac{3_C_2}{9_C_2}\\\\\\=\dfrac{1}{12}\\\\\\=0.0833$

Hence, Probability that atleast does not work is:

0.5+0.0833=0.5833

4 0

3 years ago